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$

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$ is an infix operator often seen in Haskell code. It applies the function on its left to the value on its right. At first glance this operator appears redundant, since ordinary application
(f x)
means the same as
(f $ x)
. However,
$
has the lowest, right-associative binding precedence (infixr 0), so it sometimes allows parentheses to be omitted; for example:
    f $ g $ h x  =  f (g (h x))
If
$
were omitted, the parse would be different:
    f g h x = ((f g) h) x
It is also useful in higher-order situations, such as
map ($ 0) xs
, or
zipWith ($) fs xs
.

1 Definition

$ comes from the Prelude, where it is defined as:

    infixr 0  $
    ($) :: (a -> b) -> a -> b
    f $ x = f x

2 See also