Programming performance/ArthurVanLeeuwen Haskell
From HaskellWiki
Didn't feel like thinking at all, so this is a trivial recursive solution.
Code
main = do xs <- getContents let cashheld = runStrategy 10000 . reverse . getDays . filter (\l -> head l /= '#') . filter (not . null) $ lines xs putStrLn $ "Cash held: " ++ show cashheld getDays :: [String] -> [(String,Double,Double,Double,Double,Integer,Double)] getDays = map getDay getDay :: String -> (String,Double,Double,Double,Double,Integer,Double) getDay s = getDay' $ words s where getDay' [date,open,high,low,close,volume,adjustedclose] = (date,read open,read high,read low,read close,read volume,read adjustedclose) runStrategy cash lines = runStrategy' cash lines [] runStrategy' cash lines shares = case lines of (c1:c2:_) -> if (closing c2 - closing c1) / closing c1 < - 0.03 then runStrategy' (cash * 0.9) (tail lines) ((((cash * 0.1) / closing c2), closing c2): shares) else if not . null $ shares then if (closing c2 - (snd . head $ shares)) / (snd . head $ shares) > 0.06 then runStrategy' (cash + (fst . head $ shares) * closing c2) (tail lines) (tail shares) else runStrategy' cash (tail lines) shares else runStrategy' cash (tail lines) shares [c1] -> cash + sellOff (closing c1) shares [] -> cash sellOff price shares = sum . map (* price) . map fst $ shares closing (date,open,high,low,close,volume,adjustedclose) = close
- Bug/Question: This solution will only perform one sale per day, even if multiple sales qualify, right? If recursion after a sale used lines instead of tail lines, then multiple sales could occur. Newsham 18:08, 8 March 2007 (UTC)
