# 99 questions/Solutions/15

### From HaskellWiki

< 99 questions | Solutions(Difference between revisions)

(added solution using list monad) |
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repli :: [a] -> Int -> [a] |
repli :: [a] -> Int -> [a] |
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repli xs n = concatMap (take n . repeat) xs |
repli xs n = concatMap (take n . repeat) xs |
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+ | </haskell> |
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+ | |||

+ | or, using the list monad: |
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+ | <haskell> |
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+ | repli :: [a] -> Int -> [a] |
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+ | repli xs n = xs >>= replicate n |
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</haskell> |
</haskell> |

## Revision as of 14:21, 5 August 2011

(**) Replicate the elements of a list a given number of times.

repli :: [a] -> Int -> [a] repli xs n = concatMap (replicate n) xs

or, in Pointfree style:

repli = flip $ concatMap . replicate

replicate

repli :: [a] -> Int -> [a] repli xs n = concatMap (take n . repeat) xs

or, using the list monad:

repli :: [a] -> Int -> [a] repli xs n = xs >>= replicate n