99 questions/Solutions/19

From HaskellWiki
< 99 questions‎ | Solutions
Revision as of 15:46, 13 July 2010 by Wapcaplet (talk | contribs)
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)
Jump to navigation Jump to search

(**) Rotate a list N places to the left.

Hint: Use the predefined functions length and (++).

rotate [] _ = []
rotate l 0 = l
rotate (x:xs) (n+1) = rotate (xs ++ [x]) n
rotate l n = rotate l (length l + n)

There are two separate cases:

  • If n > 0, move the first element to the end of the list n times.
  • If n < 0, convert the problem to the equivalent problem for n > 0 by adding the list's length to n.

or using cycle:

rotate xs n = take len . drop (n `mod` len) . cycle $ xs
    where len = length xs

or

rotate xs n = if n >= 0 then
                  drop n xs ++ take n xs
              else let l = ((length xs) + n) in
                  drop l xs ++ take l xs

or

rotate xs n = drop nn xs ++ take nn xs
    where 
      nn = n `mod` length xs