99 questions/Solutions/4
From HaskellWiki
(*) Find the number of elements of a list.
myLength :: [a] -> Int myLength [] = 0 myLength (_:xs) = 1 + myLength xs
myLength' = foldl (\n _ -> n + 1) 0 myLength'' = foldr (\_ n -> n + 1) 0 myLength''' = foldr (\_ -> (+1)) 0
length
Prelude
