99 questions/Solutions/46
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Now, write a predicate table/3 which prints the truth table of a given logical expression in two variables. | Now, write a predicate table/3 which prints the truth table of a given logical expression in two variables. | ||
| + | |||
| + | The first step in this problem is to define the Boolean predicates: | ||
<haskell> | <haskell> | ||
| + | -- NOT negates a single Boolean argument | ||
not' :: Bool -> Bool | not' :: Bool -> Bool | ||
not' True = False | not' True = False | ||
not' False = True | not' False = True | ||
| + | -- Type signature for remaining logic functions | ||
and',or',nor',nand',xor',impl',equ' :: Bool -> Bool -> Bool | and',or',nor',nand',xor',impl',equ' :: Bool -> Bool -> Bool | ||
| + | |||
| + | -- AND is True if both a and b are True | ||
and' True True = True | and' True True = True | ||
and' _ _ = False | and' _ _ = False | ||
| + | -- OR is True if a or b or both are True | ||
or' False False = False | or' False False = False | ||
or' _ _ = True | or' _ _ = True | ||
| + | -- NOR is the negation of 'or' | ||
nor' a b = not' $ or' a b | nor' a b = not' $ or' a b | ||
| + | |||
| + | -- NAND is the negation of 'and' | ||
nand' a b = not' $ and' a b | nand' a b = not' $ and' a b | ||
| + | -- XOR is True if either a or b is True, but not if both are True | ||
xor' True False = True | xor' True False = True | ||
xor' False True = True | xor' False True = True | ||
xor' _ _ = False | xor' _ _ = False | ||
| + | -- IMPL is True if a implies b, equivalent to (not a) or (b) | ||
impl' a b = (not' a) `or'` b | impl' a b = (not' a) `or'` b | ||
| + | -- EQU is True if a and b are equal | ||
equ' True True = True | equ' True True = True | ||
equ' False False = True | equ' False False = True | ||
equ' _ _ = False | equ' _ _ = False | ||
| + | </haskell> | ||
| - | + | The above implementations build each logic function from scratch; they could be shortened using Haskell's builtin equivalents: | |
| - | + | ||
| - | + | <haskell> | |
| + | and' a b = a && b | ||
| + | or' a b = a || b | ||
| + | nand' a b = not (and' a b) | ||
| + | nor' a b = not (or' a b) | ||
| + | xor' a b = not (equ' a b) | ||
| + | impl' a b = or' (not a) b | ||
| + | equ' a b = a == b | ||
</haskell> | </haskell> | ||
| - | + | Some could be reduced even further using [[Pointfree]] style: | |
| + | |||
| + | <haskell> | ||
| + | and' = (&&) | ||
| + | or' = (||) | ||
| + | equ' = (==) | ||
| + | </haskell> | ||
| + | |||
| + | The only remaining task is to generate the truth table; most of the complexity here comes from the string conversion and IO. The approach used here accepts a Boolean function <tt>(Bool -> Bool -> Bool)</tt>, then calls that function with all four combinations of two Boolean values, and converts the resulting values into a list of space-separated strings. Finally, the strings are printed out by mapping <hask>putStrLn</hask> across the list of strings: | ||
| + | |||
| + | <haskell> | ||
| + | table :: (Bool -> Bool -> Bool) -> IO () | ||
| + | table f = mapM_ putStrLn [show a ++ " " ++ show b ++ " " ++ show (f a b) | ||
| + | | a <- [True, False], b <- [True, False]] | ||
| + | </haskell> | ||
The table function in Lisp supposedly uses Lisp's symbol handling to substitute variables on the fly in the expression. I chose passing a binary function instead because parsing an expression would be more verbose in haskell than it is in Lisp. Template Haskell could also be used :) | The table function in Lisp supposedly uses Lisp's symbol handling to substitute variables on the fly in the expression. I chose passing a binary function instead because parsing an expression would be more verbose in haskell than it is in Lisp. Template Haskell could also be used :) | ||
| + | |||
| + | The table function can be generalized to work for any given binary function and domain. | ||
| + | <haskell> | ||
| + | table :: (Bool -> Bool -> Bool) -> String | ||
| + | table f = printBinary f [True, False] | ||
| + | |||
| + | printBinary :: (Show a, Show b) => (a -> a -> b) -> [a] -> String | ||
| + | printBinary f domain = concatMap (++ "\n") [printBinaryInstance f x y | x <- domain, y <- domain] | ||
| + | |||
| + | printBinaryInstance :: (Show a, Show b) => (a -> a -> b) -> a -> a -> String | ||
| + | printBinaryInstance f x y = show x ++ " " ++ show y ++ " " ++ show (f x y) | ||
| + | </haskell> | ||
Current revision
(**) Define predicates and/2, or/2, nand/2, nor/2, xor/2, impl/2 and equ/2 (for logical equivalence) which succeed or fail according to the result of their respective operations; e.g. and(A,B) will succeed, if and only if both A and B succeed.
A logical expression in two variables can then be written as in the following example: and(or(A,B),nand(A,B)).
Now, write a predicate table/3 which prints the truth table of a given logical expression in two variables.
The first step in this problem is to define the Boolean predicates:
-- NOT negates a single Boolean argument not' :: Bool -> Bool not' True = False not' False = True -- Type signature for remaining logic functions and',or',nor',nand',xor',impl',equ' :: Bool -> Bool -> Bool -- AND is True if both a and b are True and' True True = True and' _ _ = False -- OR is True if a or b or both are True or' False False = False or' _ _ = True -- NOR is the negation of 'or' nor' a b = not' $ or' a b -- NAND is the negation of 'and' nand' a b = not' $ and' a b -- XOR is True if either a or b is True, but not if both are True xor' True False = True xor' False True = True xor' _ _ = False -- IMPL is True if a implies b, equivalent to (not a) or (b) impl' a b = (not' a) `or'` b -- EQU is True if a and b are equal equ' True True = True equ' False False = True equ' _ _ = False
The above implementations build each logic function from scratch; they could be shortened using Haskell's builtin equivalents:
and' a b = a && b or' a b = a || b nand' a b = not (and' a b) nor' a b = not (or' a b) xor' a b = not (equ' a b) impl' a b = or' (not a) b equ' a b = a == b
Some could be reduced even further using Pointfree style:
and' = (&&) or' = (||) equ' = (==)
table :: (Bool -> Bool -> Bool) -> IO () table f = mapM_ putStrLn [show a ++ " " ++ show b ++ " " ++ show (f a b) | a <- [True, False], b <- [True, False]]
The table function in Lisp supposedly uses Lisp's symbol handling to substitute variables on the fly in the expression. I chose passing a binary function instead because parsing an expression would be more verbose in haskell than it is in Lisp. Template Haskell could also be used :)
The table function can be generalized to work for any given binary function and domain.
table :: (Bool -> Bool -> Bool) -> String table f = printBinary f [True, False] printBinary :: (Show a, Show b) => (a -> a -> b) -> [a] -> String printBinary f domain = concatMap (++ "\n") [printBinaryInstance f x y | x <- domain, y <- domain] printBinaryInstance :: (Show a, Show b) => (a -> a -> b) -> a -> a -> String printBinaryInstance f x y = show x ++ " " ++ show y ++ " " ++ show (f x y)
