# 99 questions/Solutions/6

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< 99 questions | Solutions(Difference between revisions)

(Just wanted to post a solution using a fold.) |
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<haskell> |
<haskell> |
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isPalindrome'' :: (Eq a) => [a] -> Bool |
isPalindrome'' :: (Eq a) => [a] -> Bool |
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− | isPalindrome'' xs = foldl (\acc (a,b) -> if a == b then acc else False) True input --just to be different |
+ | isPalindrome'' xs = foldl (\acc (a,b) -> if a == b then acc else False) True input |

where |
where |
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input = zip xs (reverse xs) |
input = zip xs (reverse xs) |

## Revision as of 04:53, 28 February 2011

(*) Find out whether a list is a palindrome. A palindrome can be read forward or backward; e.g. (x a m a x).

isPalindrome :: (Eq a) => [a] -> Bool isPalindrome xs = xs == (reverse xs)

isPalindrome' [] = True isPalindrome' [_] = True isPalindrome' xs = (head xs) == (last xs) && (isPalindrome' $ init $ tail xs)

Here's one to show it done in a fold just for the fun of it. Do note that it is less efficient then the previous 2 though.

isPalindrome'' :: (Eq a) => [a] -> Bool isPalindrome'' xs = foldl (\acc (a,b) -> if a == b then acc else False) True input where input = zip xs (reverse xs)