Benchmarks Game/Parallel/BinaryTrees

{-# OPTIONS -funbox-strict-fields #-}
{-# LANGUAGE BangPatterns #-}
--
-- The Computer Language Benchmarks Game
-- http://shootout.alioth.debian.org/
--
-- Contributed by Don Stewart
-- Modified by Stephen Blackheath to parallelize (a very tiny tweak)
--
-- Compile with:
--
-- >    ghc -O2 -fasm -threaded --make 
--
-- Run with:
--
-- >    ./A +RTS -N4 -H300M -RTS 20
-- 
-- Where '4' is the number of cores. and "set your -H value high (3 or
-- more times the maximum residency)", as per GHC User's Guide:
--
--  <http://haskell.org/ghc/docs/6.10.1/html/users_guide/runtime-control.html#rts-options-gc>
--
-- -H "provides a “suggested heap size” for the garbage collector. The
-- garbage collector will use about this much memory until the program
-- residency grows and the heap size needs to be expanded to retain
-- reasonable performance."
--
 
import System
import Data.Bits
import Text.Printf
import Control.Parallel.Strategies
 
--
-- an artificially strict tree.
--
-- normally you would ensure the branches are lazy, but this benchmark
-- requires strict allocation.
--
data Tree = Nil | Node !Int !Tree !Tree
 
minN = 4
 
io s n t = printf "%s of depth %d\t check: %d\n" s n t
 
main = do
    n <- getArgs >>= readIO . head
    let maxN     = max (minN + 2) n
        stretchN = maxN + 1
 
    -- stretch memory tree
    let c = check (make 0 stretchN)
    io "stretch tree" stretchN c
 
    -- allocate a long lived tree
    let !long    = make 0 maxN
 
    -- allocate, walk, and deallocate many bottom-up binary trees
    let vs = parMap rnf id $ depth minN maxN
    mapM_ (\((m,d,i)) -> io (show m ++ "\t trees") d i) vs
 
    -- confirm the the long-lived binary tree still exists
    io "long lived tree" maxN (check long)
 
-- generate many trees
depth :: Int -> Int -> [(Int,Int,Int)]
depth d m
    | d <= m    = (2*n,d,sumT d n 0) : depth (d+2) m
    | otherwise = []
  where n = 1 `shiftL` (m - d + minN)
 
-- allocate and check lots of trees
sumT :: Int -> Int -> Int -> Int
sumT d 0 t = t
sumT  d i t = sumT d (i-1) (t + a + b)
  where a = check (make i    d)
        b = check (make (-i) d)
 
-- traverse the tree, counting up the nodes
check :: Tree -> Int
check Nil          = 0
check (Node i l r) = i + check l - check r
 
-- build a tree
make :: Int -> Int -> Tree
make i 0 = Node i Nil Nil
make i d = Node i (make (i2-1) d2) (make i2 d2)
  where i2 = 2*i; d2 = d-1

{-# OPTIONS -fbang-patterns -funbox-strict-fields #-}
--
-- The Computer Language Shootout
-- http://shootout.alioth.debian.org/
--
-- Contributed by Don Stewart and Thomas Davie
--
-- This implementation uses a parallel strategy to exploit the quad core machine.
-- For more information about Haskell parallel strategies, see,
--
--  http://www.macs.hw.ac.uk/~dsg/gph/papers/html/Strategies/strategies.html
--
 
import System
import Data.Bits
import Text.Printf
import Control.Parallel.Strategies
import Control.Parallel
 
--
-- an artificially strict tree.
--
-- normally you would ensure the branches are lazy, but this benchmark
-- requires strict allocation.
--
data Tree = Nil | Node !Int !Tree !Tree
 
minN = 4
 
io s n t = printf "%s of depth %d\t check: %d\n" s n t
 
main = do
    n <- getArgs >>= readIO . head
    let maxN     = max (minN + 2) n
        stretchN = maxN + 1
 
    -- stretch memory tree
    let c = check (make 0 stretchN)
    io "stretch tree" stretchN c
 
    -- allocate a long lived tree
    let !long    = make 0 maxN
 
    -- allocate, walk, and deallocate many bottom-up binary trees
    let vs = (parMap rnf) (depth' maxN) [minN,minN+2..maxN]
    mapM_ (\((m,d,i)) -> io (show m ++ "\t trees") d i) vs
 
    -- confirm the the long-lived binary tree still exists
    io "long lived tree" maxN (check long)
 
-- generate many trees
depth' :: Int -> Int -> (Int,Int,Int)
depth' m d =
  (2*n,d,sumT d n 0)
  where
    n = 1 `shiftL` (m - d + minN)
 
-- allocate and check lots of trees
sumT :: Int -> Int -> Int -> Int
sumT d 0 t = t
sumT  d i t = sumT d (i-1) (t + a + b)
  where a = check (make i    d)
        b = check (make (-i) d)
 
-- traverse the tree, counting up the nodes
check :: Tree -> Int
check Nil          = 0
check (Node i l r) = i + check l - check r
 
-- build a tree
make :: Int -> Int -> Tree
make i 0 = Node i Nil Nil
make i d = Node i (make (i2-1) d2) (make i2 d2)
  where i2 = 2*i; d2 = d-1