Personal tools

Cookbook/Dates And Time

From HaskellWiki

< Cookbook(Difference between revisions)
Jump to: navigation, search
Current revision (17:45, 2 August 2009) (edit) (undo)
m (Difference of two dates: typo)
 
(One intermediate revision not shown.)
Line 1: Line 1:
-
= Finding today's date =
+
== Finding today's date ==
<haskell>
<haskell>
Line 8: Line 8:
</haskell>
</haskell>
-
= Adding to or subtracting from a date =
+
== Adding to or subtracting from a date ==
{| class="wikitable"
{| class="wikitable"
Line 33: Line 33:
|}
|}
-
= Difference of two dates =
+
== Difference of two dates ==
{| class="wikitable"
{| class="wikitable"
Line 46: Line 46:
import Date.Time
import Date.Time
a = fromGregorian 2009 12 31 --> 2009-12-31
a = fromGregorian 2009 12 31 --> 2009-12-31
-
b = fromGregorian 2010 12 32 --> 2010-12-31
+
b = fromGregorian 2010 12 31 --> 2010-12-31
diffDays b a --> 365
diffDays b a --> 365
</haskell>
</haskell>
|}
|}
-
= CPU time =
+
== CPU time ==
Use [http://www.haskell.org/ghc/docs/latest/html/libraries/base/System-CPUTime.html#v%3AgetCPUTime System.CPUTime.getCPUTime] to get the CPU time in picoseconds.
Use [http://www.haskell.org/ghc/docs/latest/html/libraries/base/System-CPUTime.html#v%3AgetCPUTime System.CPUTime.getCPUTime] to get the CPU time in picoseconds.

Current revision

Contents

1 Finding today's date

import Data.Time
 
c <- getCurrentTime                  --> 2009-04-21 14:25:29.5585588 UTC 
(y,m,d) = toGregorian $ utctDay c    --> (2009,4,21)

2 Adding to or subtracting from a date

Problem Solution Examples
adding days to a date addDays
import Date.Time
a = fromGregorian 2009 12 31    --> 2009-12-31
b = addDays 1 a                 --> 2010-01-01
subtracting days from a date addDays
import Date.Time
a = fromGregorian 2009 12 31    --> 2009-12-31
b = addDays (-7) a              --> 2009-12-24

3 Difference of two dates

Problem Solution Examples
calculating the difference of two dates diffDays
import Date.Time
a = fromGregorian 2009 12 31    --> 2009-12-31
b = fromGregorian 2010 12 31    --> 2010-12-31
diffDays b a                    --> 365

4 CPU time

Use System.CPUTime.getCPUTime to get the CPU time in picoseconds.

You can time a computation like this

getCPUTimeDouble :: IO Double
getCPUTimeDouble = do t <- System.CPUTime.getCPUTime; return ((fromInteger t) * 1e-12)
 
main = do
    t1 <- getCPUTimeDouble
    print (fib 30)
    t2 <- getCPUTimeDouble
    print (t2-t1)