Difference between revisions of "Cum se aplica o lista de functii pe o valoare ?"
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<haskell> |
<haskell> |
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Prelude> map ($ 0) [(1+),(2+),(23+)] |
Prelude> map ($ 0) [(1+),(2+),(23+)] |
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<haskell> |
<haskell> |
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Prelude> map ($ 1) [(\x -> x+1) , (20+), (\y -> y *y) ] |
Prelude> map ($ 1) [(\x -> x+1) , (20+), (\y -> y *y) ] |
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Revision as of 09:32, 23 January 2008
Folosind vechea noastra cunostinta map si operatorul $ putem sa transferam o singura valoare (argument) unei liste de functii:
Exemplul 1:
Prelude> map ($ 0) [(1+),(2+),(23+)]
[1,2,23]
Exemplul 2:
Prelude> map ($ 1) [(\x -> x+1) , (20+), (\y -> y *y) ]
[2,21,1]
Prelude> map ($ 2) [(\x -> x+1) , (20+), (\y -> y *y) ]
[3,22,4]
Prelude> map ($ 3) [(\x -> x+1) , (20+), (\y -> y *y) ]
[4,23,9]
Prelude>
Nota: Bineinteles ca functiile trebuie sa aiba acelasi tip.
Pagina indexata la indexul Categories:Ro
<= Inapoi la pagina principala Ro/Haskell.
<- Inapoi la Intrebarile incepatorului Ro/Haskell.