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Data.List.Split

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Revision as of 20:35, 13 December 2008 by Byorgey (Talk | contribs)

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A theoretical module which contains implementations/combinators for implementing every possible method of list-splitting known to man. This way no one has to argue about what the correct interface for split is, we can just have them all.

Some possible ways to split a list, to get your creative juices flowing:

  • what to split on?
    • single-element separator
    • sublist separator
    • use a list of possible separators instead of just one
    • use a predicate on elements or sublists instead of giving explicit separators
    • use approximate matching?
    • chunks of fixed length
  • how to split?
    • discard the separators
    • keep the separators with the preceding or following splits
    • keep the separators as their own separate pieces of the result list
    • what to do with separators at the beginning/end? create a blank split before/after, or not?

Add your implementations below! Once we converge on something good we can upload it to hackage.

{-# LANGUAGE ViewPatterns #-}
 
import Data.List (unfoldr)
 
 
-- intercalate :: [a] -> [[a]] -> [a]
-- intercalate x [a,b,c,x,y,z] = [a,x,b,x,c,x,x,y,x,z,x]
 
-- unintercalate :: [a] -> [a] -> [[a]]
-- unintercalate x [a,x,b,x,c,x,x,y,x,z,x] = [a,b,c,[],y,z]
 
-- unintercalate is the "inverse" of intercalate
 
match [] string = Just string
match (_:_) [] = Nothing
match (p:ps) (q:qs) | p == q = match ps qs
match (_:_)  (_:_)  | otherwise = Nothing
 
chopWith delimiter (match delimiter -> Just tail) = return ([], tail)
chopWith delimiter (c:cs) = chopWith delimiter cs >>= \(head, tail) ->
                              return (c:head, tail)
chopWith delimiter [] = Nothing
-- note: chopWith could be make 'more efficient' i.e. remove the >>=\-> bit
--       by adding an accumulator
 
 
unintercalate delimiter = unfoldr (chopWith delimiter)
 
-- > unintercalate "x" "axbxcxxyxzx"
-- ["a","b","c","","y","z"]
 
splitOn :: (a -> Bool) -> [a] -> [[a]]
splitOn _ [] = []
splitOn f l@(x:xs)
  | f x = splitOn f xs
  | otherwise = let (h,t) = break f l in h:(splitOn f t)
 
-- take the element who make predict true as delimiter
-- > splitOn even [1,3,5,6,7,3,3,2,1,1,1]
-- [[1,3,5],[7,3,3],[1,1,1]]
 
-- | like String split, except for any element that obeys Eq
splitEq :: Eq a => a -> [a] -> [[a]]
splitEq e = splitOn (==e)
 
-- | split at regular intervals
chunk :: Int -> [a] -> [[a]]
chunk _ [] = [[]]
chunk n xs = y1 : chunk n y2
  where
    (y1, y2) = splitAt n xs