Difference between revisions of "Enumerator and iteratee"

From HaskellWiki
Jump to navigation Jump to search
(Oleg's talk)
(link to "separation of concerns")
Line 20: Line 20:
 
iteratee to be a pair of the function to feed to fold, and the initial
 
iteratee to be a pair of the function to feed to fold, and the initial
 
seed (the accumulator in the above example). That achieves the
 
seed (the accumulator in the above example). That achieves the
separation of concerns: fold (aka, enumerator) has the intimate knowledge
+
[[separation of concerns]]: fold (aka, enumerator) has the intimate knowledge
 
of the collection and how to get to the next element; iteratee knows
 
of the collection and how to get to the next element; iteratee knows
 
what to do with the current element.
 
what to do with the current element.

Revision as of 22:00, 29 January 2009

An enumerator is something that knows how to process a data structure and an iteratee is something that does one step in processing another piece of the big data structure. E.g. to sum up all elements of Data.Map, we do

Map.fold (+) 0 mp

to sum up all elements of a set we do

Set.fold (+) 0 st

Then fold is the enumerator and (+) and 0 are the iteratee.

Ditto for any other foldable data structure. Clearly the function that sums the current element with the accumulator, (+), doesn't know or care from which collection the elements are coming from. The initial seed, 0, is again unaware of the collection.

Iteratee is indeed the function that you pass to fold (combined with the seed for practical reasons). One may conceptually consider iteratee to be a pair of the function to feed to fold, and the initial seed (the accumulator in the above example). That achieves the separation of concerns: fold (aka, enumerator) has the intimate knowledge of the collection and how to get to the next element; iteratee knows what to do with the current element.


See also