Euler problems/111 to 120

Problem 111

Search for 10-digit primes containing the maximum number of repeated digits.

Solution:

import Control.Monad (replicateM)

-- All ways of interspersing n copies of x into a list
intr :: Int -> a -> [a] -> [[a]]
intr 0 _ y      = [y]
intr n x (y:ys) = concat
                  [map ((replicate i x ++) . (y :)) $ intr (n-i) x ys
                       | i <- [0..n]]
intr n x _      = [replicate n x]

-- All 10-digit primes containing the maximal number of the digit d
maxDigits :: Char -> [Integer]
maxDigits d = head $ dropWhile null
              [filter isPrime $ map read $ filter ((/='0') . head) $
               concatMap (intr (10-n) d) $
               replicateM n $ delete d "0123456789"
                   | n <- [1..9]]
 
problem_111 = sum $ concatMap maxDigits "0123456789"

Problem 112

Investigating the density of "bouncy" numbers.

Solution:

import Data.List
digits n 
{-  change 123 to [3,2,1]
 -}
    |n<10=[n]
    |otherwise= y:digits x 
    where
    (x,y)=divMod n 10
isdecr x=
    null$filter (\(x, y)->x-y<0)$zip di k
    where
    di=digits x
    k=0:di
isincr x=
    null$filter (\(x, y)->x-y<0)$zip di k
    where
    di=digits x
    k=tail$di++[0]
nnn=1500000
num150 =length [x|x<-[1..nnn],isdecr x||isincr x]
istwo x|isdecr x||isincr x=1
     |otherwise=0
problem_112 n1 n2=
    if (div n1 n2==100)
       then do appendFile "file.log" ((show n1)  ++"   "++ (show n2)++"\n")
               return()
       else  problem_112 (n1+1) (n2+istwo (n1+1))
main=  problem_112 nnn num150

Problem 113

How many numbers below a googol (10100) are not "bouncy"?

Solution:

import Array

mkArray b f = listArray b $ map f (range b)

digits = 100

inc = mkArray ((1, 0), (digits, 9)) ninc
dec = mkArray ((1, 0), (digits, 9)) ndec

ninc (1, _) = 1
ninc (l, d) = sum [inc ! (l-1, i) | i <- [d..9]]

ndec (1, _) = 1
ndec (l, d) = sum [dec ! (l-1, i) | i <- [0..d]]

problem_113 = sum [inc ! i | i <- range ((digits, 0), (digits, 9))]
               + sum [dec ! i | i <- range ((1, 1), (digits, 9))]
               - digits*9 -- numbers like 11111 are counted in both inc and dec 
               - 1 -- 0 is included in the increasing numbers

Note: inc and dec contain the same data, but it seems clearer to duplicate them.

it is another way to solution this problem:

import List
series  2 =replicate 10 1
series n=sumkey$map (\(x, y)->map (*y) x)$zip key (series (n-1))
key =[replicate (a+1) 1++replicate (9-a) 0|a<-[0..9]]
sumkey k=[sum [a!!m|a<-k]|m<-[0..9]]
fun x= sum [(sum$series i)-1|i<-[2..x]]-(x-1)*9-1+(sum$series  x)
problem_113 =fun 101