Euler problems/141 to 150
From HaskellWiki
Contents |
1 Problem 141
Investigating progressive numbers, n, which are also square.
Solution:
import Data.List intSqrt :: Integral a => a -> a intSqrt n | n < 0 = error "intSqrt: negative n" | otherwise = f n where f x = if y < x then f y else x where y = (x + (n `quot` x)) `quot` 2 isSqrt n = n==((^2).intSqrt) n takec a b = two++takeWhile (<=e12) [sq| c1<-[1..], let c=c1*c1,let sq=(c^2*a^3*b+b^2*c) ] where e12=10^12 two=[sq|c<-[b,2*b],let sq=(c^2*a^3*b+b^2*c) ] problem_141= sum$nub[c| (a,b)<-takeWhile (\(a,b)->a^3*b+b^2<e12) [(a,b)| a<-[2..e4], b<-[1..(a-1)] ], gcd a b==1, c<-takec a b, isSqrt c ] where e4=120 e12=10^12
2 Problem 142
Perfect Square Collection
Solution:
import List isSquare n = (round . sqrt $ fromIntegral n) ^ 2 == n aToX (a,b,c)=[x,y,z] where x=div (a+b) 2 y=div (a-b) 2 z=c-x {- - 2 2 2 - a = c + d - 2 2 2 - a = e + f - 2 2 2 - c = e + b - let b=x*y then - (y + xb) - c= --------- - 2 - (-y + xb) - e= --------- - 2 - (-x + yb) - d= --------- - 2 - (x + yb) - f= --------- - 2 - - and - 2 2 2 - a = c + d - then - 2 2 2 2 - 2 (y + x ) (x y + 1) - a = --------------------- - 4 - -} problem_142 = sum$head[aToX(t,t2 ,t3)| a<-[3,5..50], b<-[(a+2),(a+4)..50], let a2=a^2, let b2=b^2, let n=(a2+b2)*(a2*b2+1), isSquare n, let t=div n 4, let t2=a2*b2, let t3=div (a2*(b2+1)^2) 4 ]
3 Problem 143
Investigating the Torricelli point of a triangle
4 Problem 144
Investigating multiple reflections of a laser beam.
Solution:
type Point = (Double, Double) type Vector = (Double, Double) type Normal = (Double, Double) sub :: Vector -> Vector -> Vector sub (x,y) (a,b) = (x-a, y-b) mull :: Double -> Vector -> Vector mull s (x,y) = (s*x, s*y) mulr :: Vector -> Double -> Vector mulr v s = mull s v dot :: Vector -> Vector -> Double dot (x,y) (a,b) = x*a + y*b normSq :: Vector -> Double normSq v = dot v v normalize :: Vector -> Vector normalize v |len /= 0 =mulr v (1.0/len) |otherwise=error "Vettore nullo.\n" where len = (sqrt . normSq) v proj :: Vector -> Vector -> Vector proj a b = mull ((dot a b)/normSq b) b reflect :: Vector -> Normal -> Vector reflect i n = sub i $ mulr (proj i n) 2.0 type Ray = (Point, Vector) makeRay :: Point -> Vector -> Ray makeRay p v = (p, v) getPoint :: Ray -> Double -> Point getPoint ((px,py),(vx,vy)) t = (px + t*vx, py + t*vy) type Ellipse = (Double, Double) getNormal :: Ellipse -> Point -> Normal getNormal (a,b) (x,y) = ((-b/a)*x, (-a/b)*y) rayFromPoint :: Ellipse -> Vector -> Point -> Ray rayFromPoint e v p = makeRay p (reflect v (getNormal e p)) test :: Point -> Bool test (x,y) = y > 0 && x >= -0.01 && x <= 0.01 intersect :: Ellipse -> Ray -> Point intersect (e@(a,b)) (r@((px,py),(vx,vy))) = getPoint r t1 where c0 = normSq (vx/a, vy/b) c1 = 2.0 * dot (vx/a, vy/b) (px/a, py/b) c2 = (normSq (px/a, py/b)) - 1.0 (t0, t1) = quadratic c0 c1 c2 quadratic :: Double -> Double -> Double -> (Double, Double) quadratic a b c |d < 0= error "Discriminante minore di zero" |otherwise= if (t0 < t1) then (t0, t1) else (t1, t0) where d = b * b - 4.0 * a * c sqrtD = sqrt d q = if b < 0 then -0.5*(b - sqrtD) else 0.5*(b + sqrtD) t0 = q / a t1 = c / q calculate :: Ellipse -> Ray -> Int -> IO () calculate e (r@(o,d)) n |test p=print n |otherwise=do putStrLn $ "\rHit " ++ show n calculate e (rayFromPoint e d p) (n+1) where p = intersect e r origin = (0.0,10.1) direction = sub (1.4,-9.6) origin ellipse = (5.0,10.0) problem_144 = do calculate ellipse (makeRay origin direction) 0
5 Problem 145
How many reversible numbers are there below one-billion?
Solution:
import List digits n {- 123->[3,2,1] -} |n<10=[n] |otherwise= y:digits x where (x,y)=divMod n 10 -- 123 ->321 dmm=(\x y->x*10+y) palind n=foldl dmm 0 (digits n) isOdd x=(length$takeWhile odd x)==(length x) isOdig x=isOdd m && s<=h where k=x+palind x m=digits k y=floor$logBase 10 $fromInteger x ten=10^y s=mod x 10 h=div x ten a2=[i|i<-[10..99],isOdig i] aa2=[i|i<-[10..99],isOdig i,mod i 10/=0] a3=[i|i<-[100..999],isOdig i] m5=[i|i1<-[0..99],i2<-[0..99], let i3=i1*1000+3*100+i2, let i=10^6* 8+i3*10+5, isOdig i ] fun i |i==2 =2*le aa2 |even i=(fun 2)*d^(m-1) |i==3 =2*le a3 |i==7 =fun 3*le m5 |otherwise=0 where le=length m=div i 2 d=2*le a2 problem_145 = sum[fun a|a<-[1..9]]
6 Problem 146
Investigating a Prime Pattern
Solution:
import List isPrime x=millerRabinPrimality x 2 --isPrime x=foldl (&& )True [millerRabinPrimality x y|y<-[2,3,7,61,24251]] six=[1,3,7,9,13,27] allPrime x=foldl (&&) True [isPrime k|a<-six,let k=x^2+a] linkPrime [x]=filterPrime x linkPrime (x:xs)=[y| a<-linkPrime xs, b<-[0..(x-1)], let y=b*prxs+a, let c=mod y x, elem c d] where prxs=product xs d=filterPrime x filterPrime p= [a| a<-[0..(p-1)], length[b|b<-six,mod (a^2+b) p/=0]==6 ] testPrimes=[2,3,5,7,11,13,17,23] primes=[2,3,5,7,11,13,17,23,29] test = sum[y| y<-linkPrime testPrimes, y<1000000, allPrime (y) ]==1242490 p146 =[y|y<-linkPrime primes,y<150000000,allPrime (y)] problem_146=[a|a<-p146, allNext a] allNext x= sum [1|(x,y)<-zip a b,x==y]==6 where a=[x^2+b|b<-six] b=head a:(map nextPrime a) nextPrime x=head [a|a<-[(x+1)..],isPrime a] main=writeFile "p146.log" $show $sum problem_146
7 Problem 147
Rectangles in cross-hatched grids
8 Problem 148
Exploring Pascal's triangle.
Solution:
triangel 0 = 0 triangel n |n <7 =n+triangel (n-1) |n==k7 =28^k |otherwise=(triangel i) + j*(triangel (n-i)) where i=k7*((n-1)`div`k7) j= -(n`div`(-k7)) k7=7^k k=floor(log (fromIntegral n)/log 7) problem_148=triangel (10^9)
9 Problem 149
Searching for a maximum-sum subsequence.
Solution:
import Data.Array import Data.List (foldl') n = 2000 res = maximum' $ concat [rows, cols, diags, diags'] where rows = map (maxSumInRow . getRow laggedFibArray) [0 .. n-1] cols = map (maxSumInRow . getCol laggedFibArray) [0 .. n-1] diags = map (maxSumInRow . getDiag laggedFibArray) [-(n-2) .. (n-2)] diags' = map (maxSumInRow . getDiag' laggedFibArray) [-(n-2) .. (n-2)] laggedFibArray :: Array Integer Integer laggedFibArray = listArray (0, n^2-1) $ map f [1..n^2] where f k = norm $ if k < 56 then 100003 - (200003*k) + (300007*(k^3)) else (laggedFibArray ! (k-25)) + (laggedFibArray ! (k-56)) + (10^6) norm x = mod x (10^6) - 500000 getRow a i = map (a!) [i*n .. (i+1)*n-1] getCol a i = map (a!) [i,n+i .. n*(n-1)+i] getDiag a i = map (a!) $ if i >= 0 then [(i*n) + (k*(n+1)) | k <- [0..n-i-1]] else [k + n*(k+i) | k <- [-i .. n-1]] getDiag' a i = map (a!) $ if i >= 0 then [(n*k) + n-k-i-1 | k <- [0..n-i-1]] else [n*(k-i) + n-k-1 | k <- [0..n+i-1]] maxSumInRow = snd . foldl' f (0,0) where f (line_sum, line_max) x = (line_sum', max line_max line_sum') where line_sum' = max (line_sum+x) 0 -- strict version of maximum maximum' (x:xs) = foldl' max x xs main = print res
10 Problem 150
Searching a triangular array for a sub-triangle having minimum-sum.
