Euler problems/161 to 170
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== [http://projecteuler.net/index.php?section=problems&id=162 Problem 162] == | == [http://projecteuler.net/index.php?section=problems&id=162 Problem 162] == | ||
Revision as of 14:26, 24 February 2008
Contents |
1 Problem 161
Triominoes
Solution: This was Robert_Gerbicz 's C code pasted from the Project Euler Forum.
2 Problem 162
Hexadecimal numbers
Solution:
numdigit=['0'..'9']++['A'..'F'] digits n |n<16=[n] |otherwise= y:digits x where (x,y)=divMod n 16 fun=(\k->15*16^(k-1)-15^(k)-2*14*15^(k-1)+13*14^(k-1)+2*14^k-13^k) fsum::Integer fsum=sum $map fun [3..16] problem_162=map ((numdigit!!).fromInteger) $reverse $digits fsum
3 Problem 163
Cross-hatched triangles
Solution:
--http://www.math.uni-bielefeld.de/~sillke/SEQUENCES/grid-triangles fun n= sum[div (2*n3 + 5*n2 + 2*n) 8 , 2*(div n3 2- div n 6) , 6* sum[div ( n*(n+1)*(n+2)) 6 , div (2*n3 + 5*n2 + 2*n) 8 , div (2*n3 + 3*n2 - 3*n) 18 , div (2*n3 + 3*n2 - 3*n) 10 ], 3 * div(22*n3 + 45*n2 - 4*n) 48 ] where n3=n*n*n n2=n*n problem_163=fun 36
4 Problem 164
Numbers for which no three consecutive digits have a sum greater than a given value.
Solution:
addDigit x = [[sum [x !! b !! c | c <- [0..9-a-b]] | b <- [0..9-a]] | a<-[0..9]] x3 = [[10-a-b | b <- [0..9-a]] | a <- [0..9]] x20 = iterate addDigit x3 !! 17 problem_164 = sum [x20 !! a !! b | a <- [1..9], b <- [0..9-a]]
5 Problem 165
Intersections
Solution:
bbsGen x = (x * x) `mod` 50515093 bbsSeq = iterate bbsGen 290797 tValues = map (`mod` 500) (tail bbsSeq) lineSeg n = take 4 (drop n tValues) lineSegs' n = lineSeg n : lineSegs' (n + 4) lineSegs = lineSegs' 0 implicitLine :: [Integer] -> (Integer, Integer, Integer) implicitLine [x1,y1,x2,y2] = (a, b, d) where a = y2 - y1 b = -(x2 - x1) d = x1*a + y1 * b within :: (Ord a, Num a, Integral b) => a -> b -> b -> Bool within a b c | b > c = within a c b | otherwise = a >= fromIntegral b && a <= fromIntegral c withinSeg :: (Ord a, Num a) => a -> a -> [Integer] -> Bool withinSeg x y l@[x1,y1,x2,y2] = within x x1 x2 && within y y1 y2 && not (endpoint x y l) endpoint :: (Ord a, Num a) => a -> a -> [Integer] -> Bool endpoint x y [x1,y1,x2,y2] = ((x == fromIntegral x1) && (y == fromIntegral y1)) || ((x == fromIntegral x2) && (y == fromIntegral y2)) boundingBoxOverlap l1@[l1x1,l1y1,l1x2,l1y2] l2@[l2x1,l2y1,l2x2,l2y2] | min l1x1 l1x2 > max l2x1 l2x2 = False | max l1x1 l1x2 < min l2x1 l2x2 = False | min l1y1 l1y2 > max l2y1 l2y2 = False | max l1y1 l1y2 < min l2y1 l2y2 = False | otherwise = True intersect :: (Fractional a, Ord a) => [Integer] -> [Integer] -> (Bool, a, a) intersect l1 l2 | boundingBoxOverlap l1 l2 && d /= 0 && withinSeg x y l1 && withinSeg x y l2 = (True, x, y) | otherwise = (False, 0, 0) where (a1, b1, d1) = implicitLine l1 (a2, b2, d2) = implicitLine l2 d = fromIntegral (a1*b2 - a2*b1) x = fromIntegral (b2 * d1 - b1 * d2) / d y = fromIntegral (a1 * d2 - a2 * d1) / d listIntersects l [] = [] listIntersects l (l1:ls) | b = [(x,y)] ++ (listIntersects l ls) | otherwise = listIntersects l ls where (b, x, y) = intersect l l1 allIntersectsList [] = [] allIntersectsList (l:ls) = listIntersects l ls ++ allIntersectsList ls problem_165 = length . quickSort . allIntersectsList $ take 5000 lineSegs quickSort :: Ord a => [(a,a)] -> [(a,a)] quickSort [] = [] quickSort (l:ls) = quickSort (filter (< l) ls) ++ [l] ++ quickSort (filter (> l) ls)
6 Problem 166
Criss Cross
Solution:
problem_166 = sum [ product (map count [[0, c, b-d, a-b-d], [0, b-a, c+d-a, b+d-a], [0, -b-c, a-b-c-d, -c-d], [0, a, d, c+d]])| a <- [-9..9], b <- [-9+a..9+a], c <- [-9..9], d <- [-9+a-c..9+a-c]] where count xs |u<l=0 |otherwise=u-l+1 where l = -minimum xs u = 9-maximum xs
7 Problem 167
Investigating Ulam sequences
8 Problem 168
Number Rotations
Solution:
fun e = sum[n*10+d| let t=[1..9], d<-t, p<-t, let (n,m)=divMod ((e-p)*d) (10*p-1) , m==0, 10*n>=e ] problem_168=flip mod (10^5)$sum[fun e|i<-[1..99],let e=10^i]
9 Problem 169
Exploring the number of different ways a number can be expressed as a sum of powers of 2.
Solution:
fusc' 0=(1,0) fusc' n |even n=(a+b, b) |odd n=(a,a+b) where (a,b)=fusc' $div n 2 fusc =fst.fusc' problem_169=fusc (10^25)
10 Problem 170
Find the largest 0 to 9 pandigital that can be formed by concatenating products.
Solution:
{- 1) The first integer must be a multiple of 3 (otherwise the digital root of the result is not 9). 2) The first integer contains at most 2 digits (otherwise the result contains more than 10 digits). 3) The first integer must be less than 49 (otherwise the result contains more than 10 digits). 4) maybe answer is 98xxxx 5) This number must be a multiple of the first factor (f). In the numbers f and cp/f all digits 1..9 have to occour once and at least one zeros. -} import Data.List permutationsOf [] = [[]] permutationsOf xs = [x:xs' | x <- xs, xs' <- permutationsOf (delete x xs)] digits =reverse.digits' where digits' n |n<10=[n] |otherwise= y:digits' x where (x,y)=divMod n 10 digitsToNum n=foldl dmm 0 n where dmm=(\x y->x*10+y) fun k xs c=any id [n/=0 && n<100|a<-k,let n=c*xs!!(a+1)] problem_170 = maximum[b| aa<-[7,6..4], a<-permutationsOf $delete aa [0..7], let b=digitsToNum $[9,8]++(aa:a), c<-[12,15..48], let (d,m)=divMod b c , m==0, let xs=digits d, (digits c++xs) \\t==[0], let k=findIndices (==0) xs, last xs/=0, fun k xs c ] where t=[0..9]
