Difference between revisions of "Euler problems/41 to 50"

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(Removing category tags. See Talk:Euler_problems)
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[[Category:Programming exercise spoilers]]
 
 
== [http://projecteuler.net/index.php?section=view&id=41 Problem 41] ==
 
== [http://projecteuler.net/index.php?section=view&id=41 Problem 41] ==
 
What is the largest n-digit pandigital prime that exists?
 
What is the largest n-digit pandigital prime that exists?
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problem_50 = findPrimeSum $ take 546 primes
 
problem_50 = findPrimeSum $ take 546 primes
 
</haskell>
 
</haskell>
 
[[Category:Tutorials]]
 
[[Category:Code]]
 

Revision as of 12:10, 30 September 2007

Problem 41

What is the largest n-digit pandigital prime that exists?

Solution:

problem_41 = head [p | n <- init (tails "987654321"),
                   p <- perms n, isPrime (read p)]
    where perms [] = [[]]
          perms xs = [x:ps | x <- xs, ps <- perms (delete x xs)]
          isPrime n = n > 1 && smallestDivisor n == n
          smallestDivisor n = findDivisor n (2:[3,5..])
          findDivisor n (testDivisor:rest)
              | n `mod` testDivisor == 0      = testDivisor
              | testDivisor*testDivisor >= n  = n
              | otherwise                     = findDivisor n rest

Problem 42

How many triangle words can you make using the list of common English words?

Solution:

score :: String -> Int
score = sum . map ((subtract 64) . ord . toUpper)

istrig :: Int -> Bool
istrig n = istrig' n trigs

istrig' :: Int -> [Int] -> Bool
istrig' n (t:ts) | n == t    = True
                 | otherwise = if t < n && head ts > n then False else  istrig' n ts

trigs = map (\n -> n*(n+1) `div` 2) [1..]
--get ws from the Euler site
ws = ["A","ABILITY" ... "YOURSELF","YOUTH"]

problem_42 = length $ filter id $ map (istrig . score) ws

Problem 43

Find the sum of all pandigital numbers with an unusual sub-string divisibility property.

Solution:

import Data.List (inits, tails)

perms :: [a] -> [[a]]
perms [] = [[]]
perms (x:xs) = [ p ++ [x] ++ s | xs' <- perms xs
                                   , (p, s) <- zip (inits xs') (tails xs') ]

check :: String -> Bool
check n = all (\x -> (read $ fst x) `mod` snd x == 0) $ zip (map (take 3) $ tail $ tails n) [2,3,5,7,11,13,17]

problem_43 :: Integer
problem_43 = foldr (\x y -> read x + y) 0 $ filter check $ perms "0123456789"

Problem 44

Find the smallest pair of pentagonal numbers whose sum and difference is pentagonal.

Solution:

combine xs = combine' [] xs
    where
        combine' acc (x:xs) = map (\n -> (n, x)) acc ++ combine' (x:acc) xs

problem_44 = d $ head $ filter f $ combine [p n| n <- [1..]]
    where
        f (a,b) = t (abs $ b-a) && t (a+b)
        d (a,b) = abs (a-b)
        p n = n*(3*n-1) `div` 2
        t n = p (fromInteger(round((1+sqrt(24*fromInteger(n)+1))/6))) == n

Problem 45

After 40755, what is the next triangle number that is also pentagonal and hexagonal?

Solution:

problem_45 =  head . dropWhile (<= 40755) $ match tries (match pents hexes)
    where match (x:xs) (y:ys)
              | x < y  = match xs (y:ys)
              | y < x  = match (x:xs) ys
              | otherwise = x : match xs ys
          tries = [n*(n+1) `div` 2   | n <- [1..]]
          pents = [n*(3*n-1) `div` 2 | n <- [1..]]
          hexes = [n*(2*n-1)         | n <- [1..]]

Problem 46

What is the smallest odd composite that cannot be written as the sum of a prime and twice a square?

Solution:

This solution is inspired by exercise 3.70 in Structure and Interpretation of Computer Programs, (2nd ed.).

problem_46 = head $ oddComposites `orderedDiff` gbSums

oddComposites = filter ((>1) . length . primeFactors) [3,5..]

gbSums = map gbWeight $ weightedPairs gbWeight primes [2*n*n | n <- [1..]]
gbWeight (a,b) = a + b

weightedPairs w (x:xs) (y:ys) =
    (x,y) : mergeWeighted w (map ((,)x) ys) (weightedPairs w xs (y:ys))

mergeWeighted w (x:xs)  (y:ys)
    | w x <= w y  = x : mergeWeighted w xs (y:ys)
    | otherwise   = y : mergeWeighted w (x:xs) ys

x `orderedDiff` [] = x
[] `orderedDiff` y = []
(x:xs) `orderedDiff` (y:ys)
    | x < y     = x : xs `orderedDiff` (y:ys)
    | x > y     = (x:xs) `orderedDiff` ys
    | otherwise = xs `orderedDiff` ys

Problem 47

Find the first four consecutive integers to have four distinct primes factors.

Solution:

import Data.List (group)

factor_lengths :: [(Integer,Int)]
factor_lengths = [(n, length $ group $ primeFactors n)| n <- [2..]]

problem_47 :: Integer
problem_47 = f factor_lengths
    where
        f (a:b:c:d:xs)
            | 4 == snd a && snd a == snd b && snd b == snd c && snd c == snd d = fst a
            | otherwise = f (b:c:d:xs)

Problem 48

Find the last ten digits of 11 + 22 + ... + 10001000.

Solution: If the problem were more computationally intensive, modular exponentiation might be appropriate. With this problem size the naive approach is sufficient.

problem_48 = sum [n^n | n <- [1..1000]] `mod` 10^10

Problem 49

Find arithmetic sequences, made of prime terms, whose four digits are permutations of each other.

Solution:

I'm new to haskell, improve here :-)

I tidied up your solution a bit, mostly by using and composing library functions where possible...makes it faster on my system. Jim Burton 10:02, 9 July 2007 (UTC)

import Data.List

isprime :: (Integral a) => a -> Bool
isprime n = isprime2 2
    where isprime2 x | x < n     = if n `mod` x == 0 then False else isprime2 (x+1)
                     | otherwise = True
 

-- 'each' works like this: each (4,1234) => [1,2,3,4]
each :: (Int, Int) -> [Int]
each = unfoldr (\(o,y) -> let x = 10 ^ (o-1) 
                              (d,m) = y `divMod` x in
                          if o == 0 then Nothing else Just (d,(o-1,m)))

ispermut :: Int -> Int -> Bool
ispermut = let f = (sort . each . (,) 4) in (. f) . (==) . f

isin :: (Eq a) => a -> [[a]] -> Bool
isin = any . elem 

problem_49_1 :: [Int] -> [[Int]] -> [[Int]]
problem_49_1 [] res = res
problem_49_1 (pr:prims) res = problem_49_1 prims res'
    where res' = if pr `isin` res then res else res ++ [pr:(filter (ispermut pr) (pr:prims))]

problem_49 :: [[Int]]
problem_49 = problem_49_1 [n | n <- [1000..9999], isprime n] []

Problem 50

Which prime, below one-million, can be written as the sum of the most consecutive primes?

Solution: (prime and isPrime not included)

findPrimeSum ps | isPrime sumps = Just sumps
                | otherwise     = findPrimeSum (tail ps) `mplus` findPrimeSum (init ps)
    where sumps = sum ps

problem_50 = findPrimeSum $ take 546 primes