# Foldl as foldr

### From HaskellWiki

(foldlMaybeMonoid) |
(→See also: + Foldr Foldl Foldl', Fold) |
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that both <hask>foldl</hask> and <hask>foldl'</hask> can be expressed as <hask>foldr</hask>. |
that both <hask>foldl</hask> and <hask>foldl'</hask> can be expressed as <hask>foldr</hask>. |
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(<hask>foldr</hask> may [http://www.willamette.edu/~fruehr/haskell/evolution.html lean so far right] it came back left again.) |
(<hask>foldr</hask> may [http://www.willamette.edu/~fruehr/haskell/evolution.html lean so far right] it came back left again.) |
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− | The converse is not true, since <hask>foldr</hask> may work on infinite lists, |
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− | which <hask>foldl</hask> variants never can do. |
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It holds |
It holds |
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<haskell> |
<haskell> |
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foldr (\b g x -> g (f x b)) id bs a |
foldr (\b g x -> g (f x b)) id bs a |
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</haskell> |
</haskell> |
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+ | |||

+ | |||

+ | (The converse is not true, since <hask>foldr</hask> may work on infinite lists, |
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+ | which <hask>foldl</hask> variants never can do. However, for ''finite'' lists, <hask>foldr</hask> ''can'' also be written in terms of <hask>foldl</hask> (although losing laziness in the process), in a similar way like this: |
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+ | <haskell> |
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+ | foldr :: (b -> a -> a) -> a -> [b] -> a |
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+ | foldr f a bs = |
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+ | foldl (\g b x -> g (f b x)) id bs a |
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+ | </haskell> |
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+ | ) |
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Now the question are: |
Now the question are: |
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map (UpdateMaybe . flip f) bs |
map (UpdateMaybe . flip f) bs |
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</haskell> |
</haskell> |
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+ | |||

+ | |||

+ | == Practical example: Parsing numbers using a bound == |
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+ | |||

+ | As a practical example consider a function that converts an integer string to an integer, |
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+ | but that aborts when the number exceeds a given bound. |
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+ | With this bound it is possible to call <hask>readBounded 1234 $ repeat '1'</hask> |
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+ | which will terminate with <hask>Nothing</hask>. |
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+ | <haskell> |
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+ | readBounded :: Integer -> String -> Maybe Integer |
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+ | readBounded bound str = |
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+ | case str of |
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+ | "" -> Nothing |
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+ | "0" -> Just 0 |
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+ | _ -> foldr |
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+ | (\digit addLeastSig mostSig -> |
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+ | let n = mostSig*10 + toInteger (Char.digitToInt digit) |
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+ | in guard (Char.isDigit digit) >> |
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+ | guard (not (mostSig==0 && digit=='0')) >> |
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+ | guard (n <= bound) >> |
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+ | addLeastSig n) |
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+ | Just str 0 |
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+ | |||

+ | readBoundedMonoid :: Integer -> String -> Maybe Integer |
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+ | readBoundedMonoid bound str = |
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+ | case str of |
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+ | "" -> Nothing |
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+ | "0" -> Just 0 |
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+ | _ -> |
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+ | let m digit = |
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+ | UpdateMaybe $ \mostSig -> |
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+ | let n = mostSig*10 + toInteger (Char.digitToInt digit) |
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+ | in guard (Char.isDigit digit) >> |
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+ | guard (not (mostSig==0 && digit=='0')) >> |
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+ | guard (n <= bound) >> |
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+ | Just n |
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+ | in evalUpdateMaybe (mconcat $ map m str) 0 |
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+ | </haskell> |
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+ | |||

+ | == See also == |
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+ | |||

+ | * Graham Hutton: [http://www.cs.nott.ac.uk/~gmh/fold.pdf A tutorial on the universality and expressiveness of fold] |
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+ | * [[Fold]] |
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+ | * [[Foldr Foldl Foldl']] |
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[[Category:Idioms]] |
[[Category:Idioms]] |

## Latest revision as of 11:01, 21 November 2011

When you wonder whether to choose foldl or foldr you may remember,

that bothIt holds

foldl :: (a -> b -> a) -> a -> [b] -> a foldl f a bs = foldr (\b g x -> g (f x b)) id bs a

*finite*lists,

*can*also be written in terms of

foldr :: (b -> a -> a) -> a -> [b] -> a foldr f a bs = foldl (\g b x -> g (f b x)) id bs a

)

Now the question are:

- How can someone find a convolved expression like this?
- How can we benefit from this rewrite?

## Contents |

## [edit] 1 Folding by concatenating updates

Instead of thinking in terms ofI find it easier to imagine a fold as a sequence of updates. An update is a function mapping from an old value to an updated new value.

newtype Update a = Update {evalUpdate :: a -> a}

We need a way to assemble several updates.

To this end we define ainstance Monoid (Update a) where mempty = Update id mappend (Update x) (Update y) = Update (y.x)

Now left-folding is straight-forward.

foldlMonoid :: (a -> b -> a) -> a -> [b] -> a foldlMonoid f a bs = flip evalUpdate a $ mconcat $ map (Update . flip f) bs

mconcat :: Monoid a => [a] -> a mconcat = foldr mappend mempty

By the way:

## [edit] 2 foldl which may terminate early

The answer to the second question is:

Using thethat behave slightly different from the original one.

E.g. we can write aand thus may also terminate on infinite input.

The functionfoldlMaybe :: (a -> b -> Maybe a) -> a -> [b] -> Maybe a foldlMaybe f a bs = foldr (\b g x -> f x b >>= g) Just bs a

Maybe the monoidic version is easier to understand. The implementation of the fold is actually the same, we do only use a different monoid.

import Control.Monad ((>=>), ) newtype UpdateMaybe a = UpdateMaybe {evalUpdateMaybe :: a -> Maybe a} instance Monoid (UpdateMaybe a) where mempty = UpdateMaybe Just mappend (UpdateMaybe x) (UpdateMaybe y) = UpdateMaybe (x>=>y) foldlMaybeMonoid :: (a -> b -> Maybe a) -> a -> [b] -> Maybe a foldlMaybeMonoid f a bs = flip evalUpdateMaybe a $ mconcat $ map (UpdateMaybe . flip f) bs

## [edit] 3 Practical example: Parsing numbers using a bound

As a practical example consider a function that converts an integer string to an integer, but that aborts when the number exceeds a given bound.

With this bound it is possible to callreadBounded :: Integer -> String -> Maybe Integer readBounded bound str = case str of "" -> Nothing "0" -> Just 0 _ -> foldr (\digit addLeastSig mostSig -> let n = mostSig*10 + toInteger (Char.digitToInt digit) in guard (Char.isDigit digit) >> guard (not (mostSig==0 && digit=='0')) >> guard (n <= bound) >> addLeastSig n) Just str 0 readBoundedMonoid :: Integer -> String -> Maybe Integer readBoundedMonoid bound str = case str of "" -> Nothing "0" -> Just 0 _ -> let m digit = UpdateMaybe $ \mostSig -> let n = mostSig*10 + toInteger (Char.digitToInt digit) in guard (Char.isDigit digit) >> guard (not (mostSig==0 && digit=='0')) >> guard (n <= bound) >> Just n in evalUpdateMaybe (mconcat $ map m str) 0