Haskell Quiz/DayRange/Solution Jethr0
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(Difference between revisions)
m (using a datatype, added type declarations) |
m (using a modified version of groupBy) |
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| Line 4: | Line 4: | ||
-- > dayRange [1,2,3,6,7] | -- > dayRange [1,2,3,6,7] | ||
-- "Mon-Wed, Sat, Sun" | -- "Mon-Wed, Sat, Sun" | ||
| - | + | module DayRange where | |
| + | import Data.List (intersperse,sort) | ||
| + | -- > dayRange [1,2,3,6,7] | ||
| + | -- "Mon-Wed, Sat, Sun" | ||
| + | data Weekday = Mon | Tue | Wed | Thu | Fri | Sat | Sun deriving (Show,Enum) | ||
| + | |||
dayRange :: [Int] -> String | dayRange :: [Int] -> String | ||
| - | dayRange = sepComma . map range . map (map toWeekday) . | + | dayRange = sepComma . map range . map (map toWeekday) . groupBy' (\a b -> a+1 == b) . sort |
where sepComma = concat . intersperse ", " | where sepComma = concat . intersperse ", " | ||
toWeekday x = show $ (toEnum (x-1) :: Weekday) | toWeekday x = show $ (toEnum (x-1) :: Weekday) | ||
| Line 13: | Line 18: | ||
| otherwise = head xs ++ "-" ++ last xs | | otherwise = head xs ++ "-" ++ last xs | ||
| - | -- | + | -- groupBy compares any element to the first one of the group |
| - | + | -- groupBy' instead compares an element to the last added group element | |
| - | + | groupBy' :: (a -> a -> Bool) -> [a] -> [[a]] | |
| - | where | + | groupBy' f (x:xs) = gb f xs [[x]] |
| - | else ( | + | where gb f (x:xs) ((a:as):bs) = gb f xs $ if f a x then ((x:a:as):bs) |
| - | + | else ([x]:(a:as):bs) | |
| + | gb _ [] as = reverse . map reverse $ as | ||
</haskell> | </haskell> | ||
Revision as of 17:41, 10 January 2007
-- > dayRange [1,2,3,6,7] -- "Mon-Wed, Sat, Sun" module DayRange where import Data.List (intersperse,sort) -- > dayRange [1,2,3,6,7] -- "Mon-Wed, Sat, Sun" data Weekday = Mon | Tue | Wed | Thu | Fri | Sat | Sun deriving (Show,Enum) dayRange :: [Int] -> String dayRange = sepComma . map range . map (map toWeekday) . groupBy' (\a b -> a+1 == b) . sort where sepComma = concat . intersperse ", " toWeekday x = show $ (toEnum (x-1) :: Weekday) range xs | length xs < 3 = sepComma xs | otherwise = head xs ++ "-" ++ last xs -- groupBy compares any element to the first one of the group -- groupBy' instead compares an element to the last added group element groupBy' :: (a -> a -> Bool) -> [a] -> [[a]] groupBy' f (x:xs) = gb f xs [[x]] where gb f (x:xs) ((a:as):bs) = gb f xs $ if f a x then ((x:a:as):bs) else ([x]:(a:as):bs) gb _ [] as = reverse . map reverse $ as
