Haskell Quiz/FizzBuzz/Solution Ninju
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I think this is probably what I'd do in the interview situation - i.e. the first and most obvious thing that comes to mind. (Alex Watt)
module Main where
main :: IO ()
main = printAll $ map fizzBuzz [1..100]
where
printAll [] = return ()
printAll (x:xs) = putStrLn x >> printAll xs
fizzBuzz :: Integer -> String
fizzBuzz n | n `mod` 15 == 0 = "FizzBuzz"
| n `mod` 5 == 0 = "Fizz"
| n `mod` 3 == 0 = "Buzz"
| otherwise = show n
An alternate solution:
module Main where
main :: IO ()
main = do
mapM_ putStrLn $ zipWith xor fizzbuzz $ map show [1..100 :: Int]
where
loop n s = cycle $ replicate (n-1) "" ++ [s]
fizzbuzz = zipWith (++) (loop 3 "Fizz") (loop 5 "Buzz")
xor s t = if null s then t else s