Indent

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Revision as of 23:18, 5 April 2006

1 Indenting Haskell Mechanically

indent(1) is a tool to format C program source. At the time of writing we have no such tool for Haskell in common use -- although this would be fairly easy to write, given the existing parsing and pretty printing libraries.

Here are some other solutions

1.1 Emacs

Emacs has an indent mode. Though it is often considered poor at laying out Haskell code.

1.2 Use GHC

GHC provides a --ddump-parsed flag. It can be used as follows. Note that it will strip comments -- so take care! It will also normalise values -- so 0xdeadbeef becomes a large decimal.

main = do  {
        ;print (f 10)
                ;      print (f 20)
       ;print (f 0xdeadbeef)       
    }                                                                                                 
    f x = sqrt  ( fromIntegral 
            (x * 10133123 `mod` 
                        1231111121 :: Int ))

Running it through:

$ ghc -fno-code -ddump-parsed B.hs
                                     
==================== Parser ====================
main = do                                       
         print (f 10)
         print (f 20)
         print (f 3735928559)
f x = sqrt (fromIntegral ((x * 10133123) `mod` 1231111121 :: Int))

Postprocess:

$ ghc -fno-code -ddump-parsed B.hs | sed '/^===/d'

main = do
         print (f 10)
         print (f 20)
         print (f 3735928559)
f x = sqrt (fromIntegral ((x * 10133123) `mod` 1231111121 :: Int))

Which is a reasonable result.

1.3 Use ghc-api

?

1.4 Use Language.Haskell

For Haskell98, this program should do the trick:

import Language.Haskell.Parser
import Language.Haskell.Pretty
 
main = interact $ \s ->
    case parseModule s of
        ParseFailed loc str -> (show loc)      ++ "\n"
        ParseOk m           -> (prettyPrint m) ++ "\n"

For example:

$ ghc -O Ppr.hs -package haskell-src

$ ./a.out < Ppr.hs

module Main (main) where
import Language.Haskell.Parser
import Language.Haskell.Pretty
main
   = interact $
       \ s ->
         case parseModule s of
             ParseFailed loc str -> (show loc) ++ "\n"
             ParseOk m -> (prettyPrint m) ++ "\n"

Or:

main =  
   let {
       x = 7;
          } in 
 
              return (
                x + x
                        )

Becomes:

module Main (main) where
 main = let x = 7 in return (x + x)

Category: Idioms