Key-value apply
From HaskellWiki
(Difference between revisions)
(Data.Map can be used) |
(Nice one...) |
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== Data.Map == | == Data.Map == | ||
| - | When you are making excessive use of (key,value) pairs it is usually time to switch to Data.Map. <hask>apply</hask> is almost the same as <hask>Data.Map.insertWith</hask>, only that function has the type: | + | When you are making excessive use of (key,value) pairs it is usually time to switch to <hask>Data.Map</hask>. Your <hask>apply</hask> function is almost the same as <hask>Data.Map.insertWith</hask>, only that function has the type: |
<haskell> | <haskell> | ||
insertWith :: Ord k => (a -> a -> a) -> k -> a -> Map k a -> Map k a | insertWith :: Ord k => (a -> a -> a) -> k -> a -> Map k a -> Map k a | ||
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Here the update function receives the new value as well. | Here the update function receives the new value as well. | ||
--[[User:Twanvl|Twanvl]] | --[[User:Twanvl|Twanvl]] | ||
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| + | Thanks for the tip! A whole new module for me to learn. My oh my... I do love the way Haskell type signatures almost tell you what the whole function does! | ||
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| + | [[User:MathematicalOrchid|MathematicalOrchid]] 19:27, 15 February 2007 (UTC) | ||
[[Category:Code]] | [[Category:Code]] | ||
Revision as of 19:27, 15 February 2007
I just wrote this function:
apply :: (Ord k) => k -> v -> (v -> v) -> [(k,v)] -> [(k,v)] apply k v f ds = let (p1,px) = span ( (k >) . fst) ds (p2,p3) = case px of [] -> ((k,v),[]) (x:xs) -> if fst x == k then ((k, f $ snd x), xs) else ((k, v), x:xs) in p1 ++ (p2 : p3)
As you can see (?!), this takes a list of key/value pairs and processes it as follows:
- The function is given a key to look for.
- If the key is found, a function is applied to the associated value.
- If the key is not found, it is inserted (at the correct place) with a specified 'default value'.
apply
apply
Ord
apply
Data.Map
When you are making excessive use of (key,value) pairs it is usually time to switch toData.Map
apply
Data.Map.insertWith
insertWith :: Ord k => (a -> a -> a) -> k -> a -> Map k a -> Map k a
Here the update function receives the new value as well. --Twanvl
-
Thanks for the tip! A whole new module for me to learn. My oh my... I do love the way Haskell type signatures almost tell you what the whole function does!
MathematicalOrchid 19:27, 15 February 2007 (UTC)
