Let vs. Where
From HaskellWiki
This seems to be only a matter of taste in the sense of "Declaration vs. expression style", however there is more to it.
It is important to know thatContents |
1 Advantages of let
Suppose you have the function
f :: s -> (a,s) f x = y where y = ... x ...
However, transforming to
f :: State s a f = State $ \x -> y where y = ... x ...
f :: s -> (a,s) f x = let y = ... x ... in y
This is easily transformed to:
f :: State s a f = State $ \x -> let y = ... x ... in y
2 Advantages of where
Because "where" blocks are bound to a syntactic construct, they can be used to share bindings between parts of a function that are not syntactically expressions. For example:
f x | cond1 x = a | cond2 x = g a | otherwise = f (h x a) where a = w x
f x = let a = w x in case () of _ | cond1 x -> a | cond2 x -> g a | otherwise -> f (h x a)
or a functional equivalent:
f x = let a = w x in select (f (h x a)) [(cond1 x, a), (cond2 x, g a)]
or a series of if-then-else expressions:
f x = let a = w x in if cond1 x then a else if cond2 x then g a else f (h x a)
3 Lambda Lifting
One other approach to consider is that let or where can often be implemented using lambda lifting and let floating, incurring at least the cost of introducing a new name. The above example:
f x | cond1 x = a | cond2 x = g a | otherwise = f (h x a) where a = w x
could be implemented as:
f x = f' (w x) x f' a x | cond1 x = a | cond2 x = g a | otherwise = f (h x a)
4 Problems with where
If you run both
fib = (map fib' [0 ..] !!) where fib' 0 = 0 fib' 1 = 1 fib' n = fib (n - 1) + fib (n - 2)
and
fib x = map fib' [0 ..] !! x where fib' 0 = 0 fib' 1 = 1 fib' n = fib (n - 1) + fib (n - 2)
you will notice, that the second one runs considerably slower than the first one.
You may wonder, why just adding the explicit argument toreduces the performance dramatically.
You might see the reason better, if you rewrite this code usingCompare
fib = let fib' 0 = 0 fib' 1 = 1 fib' n = fib (n - 1) + fib (n - 2) in (map fib' [0 ..] !!)
and
fib x = let fib' 0 = 0 fib' 1 = 1 fib' n = fib (n - 1) + fib (n - 2) in map fib' [0 ..] !! x
thus it cannot be floated out.
In contrast to that, in the first case- Haskell-Cafe on Eta-expansion destroys memoization?
