Difference between revisions of "Non-strict semantics"
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You will not be able to define a function <code>or</code> say in C which returns something if you pass an undefined value (e.g. one that is the result of an infinite loop). In fact, in <code>or(true,infinite_loop())</code>, the code of <code>or</code> will never be run. In Haskell it is possible because you [[Call by demand]]. |
You will not be able to define a function <code>or</code> say in C which returns something if you pass an undefined value (e.g. one that is the result of an infinite loop). In fact, in <code>or(true,infinite_loop())</code>, the code of <code>or</code> will never be run. In Haskell it is possible because you [[Call by demand]]. |
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| + | ==See also== |
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| + | * Jonathan Cast in Haskell Cafe about [http://www.haskell.org/pipermail/haskell-cafe/2007-November/034807.html What is the role of $! ?] |
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[[Category:Glossary]] |
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Revision as of 10:45, 18 November 2007
Non-strict semantics means that a function can have a definite value although its argument is undefined. E.g. in Haskell you get
Prelude> True || undefined
True
You will not be able to define a function or say in C which returns something if you pass an undefined value (e.g. one that is the result of an infinite loop). In fact, in or(true,infinite_loop()), the code of or will never be run. In Haskell it is possible because you Call by demand.
See also
- Jonathan Cast in Haskell Cafe about What is the role of $! ?