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Pronunciation

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(lambda)
(a bit of expansion.)
Line 8: Line 8:
   
 
<hask> -< </hask>
 
<hask> -< </hask>
  +
  +
<hask> = </hask> equals
   
 
<hask> => </hask> is a witness for, implies
 
<hask> => </hask> is a witness for, implies
   
<hask> . </hask> ring, dot
+
<hask> . </hask> dot (could be used anywhere, but especially in, for example, Data.Char.ord), ring, compose (for example, negate . (+1)), (silent) (for example, forall a. (Num a) => a)
   
 
<hask> <- </hask> drawn from, from
 
<hask> <- </hask> drawn from, from
Line 20: Line 22:
   
 
<hask> >>= </hask> bind
 
<hask> >>= </hask> bind
  +
  +
<hask> >> </hask>
   
 
<hask>f :: Int -> Int</hask> f has type Int to Int
 
<hask>f :: Int -> Int</hask> f has type Int to Int
   
<hask>\</hask> lambda
+
<hask> \ </hask> lambda
   
  +
should we add informal, possibly bad suggestions like "then", "is", "gets"?
   
   

Revision as of 17:50, 8 January 2008

Some notes for beginners on how to pronounce those strange Haskell operators etc.

This is just a rough start to this page. Obviously needs more work.

This can be a table with formal and informal ways of saying various operators and code snippets such as

 ->
maps to, to
 -<
 =
equals
 =>
is a witness for, implies
 .
dot (could be used anywhere, but especially in, for example, Data.Char.ord), ring, compose (for example, negate . (+1)), (silent) (for example, forall a. (Num a) => a)
 <-
drawn from, from
 ++
append
 +++
 >>=
bind
 >>
f :: Int -> Int
f has type Int to Int
 \
lambda

should we add informal, possibly bad suggestions like "then", "is", "gets"?