Simple StateT use
From HaskellWiki
A small example showing how to combine a State monad (in this case a unique supply), with the IO monad, via a monad transformer.
No need to resort to nasty mutable variables or globals!
import Control.Monad.State main :: IO () main = runStateT code [1..] >> return () -- -- layer an infinite list of uniques over the IO monad -- code :: StateT [Integer] IO () code = do x <- pop io $ print x y <- pop io $ print y return () -- -- pop the next unique off the stack -- pop :: StateT [Integer] IO Integer pop = do (x:xs) <- get put xs return x io :: IO a -> StateT [Integer] IO a io = liftIO -- -- another example: a guessing game -- (from http://scsibug.com/2006/11/28/a-simple-game-with-statet/) -- module Main where import System.Random import Control.Monad.State main = do answer <- getStdRandom (randomR (1,100)) -- think of a number putStrLn "I'm thinking of a number between 1 and 100, can you guess it?" guesses <- execStateT (guessSession answer) 0 putStrLn $ "Success in " ++ (show guesses) ++ " tries." guessSession :: Int -> StateT Int IO () guessSession answer = do gs <- lift getLine -- get guess from user let g = read gs -- convert to number modify (+1) -- increment number of guesses case compare g answer of LT -> do lift $ putStrLn "Too low" guessSession answer GT -> do lift $ putStrLn "Too high" guessSession answer EQ -> lift $ putStrLn "Got it!"
Categories: Code | Monad
