Difference between revisions of "Talk:99 questions/Solutions/18"
Jump to navigation
Jump to search
Rbirenheide (talk | contribs) |
Rbirenheide (talk | contribs) m |
||
| Line 4: | Line 4: | ||
slice xs (i+1) k = snd (split (fst (split xs k)) i) |
slice xs (i+1) k = snd (split (fst (split xs k)) i) |
||
</haskell> |
</haskell> |
||
| + | |||
| + | |||
The solution: |
The solution: |
||
| − | < |
+ | <haskell>slice xs i k | i>0 = take (k-i+1) $ drop (i-1) xs</haskell> |
will not give proper results for negative indices particularly when the first index is negative and the second one within the length of the list. |
will not give proper results for negative indices particularly when the first index is negative and the second one within the length of the list. |
||
Latest revision as of 08:29, 30 May 2012
Hi. I'm wondering if this solution still works in the current Haskell version.
slice xs (i+1) k = snd (split (fst (split xs k)) i)
The solution:
slice xs i k | i>0 = take (k-i+1) $ drop (i-1) xs
will not give proper results for negative indices particularly when the first index is negative and the second one within the length of the list.