Talk:Anagrams

This is something I threw together in my spare time at work to play with Data.ByteString. I'm sure there are things that could be done better; please improve as you wish and leave notes and reasoning on this page. Thanks!

Ideas:

• B.group is apparently quite slow. Perhaps it would be faster to do something like:

[CharCount n (B.count n s) | n <- ['A'..'Z'], s <- strings]
-- or
[B.foldl' (\cl c -> updateAssocListSomehow c) s [] | s <- strings]

• The [CharCount] representation may not be the most efficient. A 27 integer UArray could be faster. Then again, I haven't profiled the code and wasn't aiming for raw speed, so.. *shrug*