Difference between revisions of "Testing primality"

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import Data.Maybe (listToMaybe)
 
import Data.Maybe (listToMaybe)
   
factors n = unfoldr (\(d, n) -> listToMaybe [(x, (x, div n x))
+
factors n = unfoldr (\(d,n) -> listToMaybe [(x, (x, div n x)) | n > 1,
| n > 1, x <- [d..isqrt n] ++ [n], rem n x == 0]) (2,n)
+
x <- [d..isqrt n] ++ [n], rem n x == 0]) (2,n)
   
isPrime n = factors n == [n]
+
isPrime n = n > 1 && factors n == [n]
 
isqrt n = floor . sqrt . fromIntegral $ n
 
isqrt n = floor . sqrt . fromIntegral $ n
 
</haskell>
 
</haskell>
   
  +
The factors produced by this code are all prime by construction, because we enumerate possible divisors in ascending order while dividing each found factor out of the number being tested.
Of course there's no need to try any even numbers above 2. Given an infinite list of primes we can avoid any composites:
 
  +
 
Of course there's no need to try any even numbers above 2 (which this code does). Given an infinite list of primes we can avoid ''any'' composites, not just evens. Re-writing the above as a recursive code, we get better control over the candidate divisors:
   
 
<haskell>
 
<haskell>
Line 34: Line 36:
 
</haskell>
 
</haskell>
   
When trying to factorize only one number or two, it will be faster to just use <code>(2:[3,5..])</code> as a source of possible divisors instead of first finding prime numbers and then using them. For more than a few factorizations, when no other primes source is available, just use
+
When trying to factorize only one number or two, it might be faster to just use <code>(2:[3,5..])</code> as a source of possible divisors instead of calculating the prime numbers first, depending on the speed of your primes generator. For more than a few factorizations, when no other primes source is available, just use
 
<haskell>
 
<haskell>
 
primes = 2 : filter isPrime [3,5..]
 
primes = 2 : filter isPrime [3,5..]

Revision as of 23:59, 22 August 2014

Testing Primality

(for a context to this see Prime numbers).

Primality Test and Integer Factorization

Simplest primality test and integer factorization is by trial division:

import Data.List (unfoldr)
import Data.Maybe (listToMaybe)

factors n = unfoldr (\(d,n) -> listToMaybe [(x, (x, div n x)) | n > 1, 
                           x <- [d..isqrt n] ++ [n], rem n x == 0]) (2,n)

isPrime n = n > 1 && factors n == [n]
isqrt n = floor . sqrt . fromIntegral $ n

The factors produced by this code are all prime by construction, because we enumerate possible divisors in ascending order while dividing each found factor out of the number being tested.

Of course there's no need to try any even numbers above 2 (which this code does). Given an infinite list of primes we can avoid any composites, not just evens. Re-writing the above as a recursive code, we get better control over the candidate divisors:

isPrime n = n > 1 &&
              foldr (\p r -> p*p > n || ((n `rem` p) /= 0 && r))
                True primes

primeFactors n | n > 1 = go n primes   -- or go n (2:[3,5..])
   where                               -- for one-off invocation
     go n ps@(p:t)
        | p*p > n    = [n]
        | r == 0     =  p : go q ps
        | otherwise  =      go n t
                where
                  (q,r) = quotRem n p

When trying to factorize only one number or two, it might be faster to just use (2:[3,5..]) as a source of possible divisors instead of calculating the prime numbers first, depending on the speed of your primes generator. For more than a few factorizations, when no other primes source is available, just use

primes = 2 : filter isPrime [3,5..]

More at Prime numbers#Optimal trial division.

Miller-Rabin Primality Test

-- (eq. to) find2km (2^k * n) = (k,n)
find2km :: Integral a => a -> (a,a)
find2km n = f 0 n
    where 
        f k m
            | r == 1 = (k,m)
            | otherwise = f (k+1) q
            where (q,r) = quotRem m 2        

-- n is the number to test; a is the (presumably randomly chosen) witness
millerRabinPrimality :: Integer -> Integer -> Bool
millerRabinPrimality n a
    | a <= 1 || a >= n-1 = 
        error $ "millerRabinPrimality: a out of range (" 
              ++ show a ++ " for "++ show n ++ ")" 
    | n < 2 = False
    | even n = False
    | b0 == 1 || b0 == n' = True
    | otherwise = iter (tail b)
    where
        n' = n-1
        (k,m) = find2km n'
        b0 = powMod n a m
        b = take (fromIntegral k) $ iterate (squareMod n) b0
        iter [] = False
        iter (x:xs)
            | x == 1 = False
            | x == n' = True
            | otherwise = iter xs

-- (eq. to) pow' (*) (^2) n k = n^k
pow' :: (Num a, Integral b) => (a->a->a) -> (a->a) -> a -> b -> a
pow' _ _ _ 0 = 1
pow' mul sq x' n' = f x' n' 1
    where 
        f x n y
            | n == 1 = x `mul` y
            | r == 0 = f x2 q y
            | otherwise = f x2 q (x `mul` y)
            where
                (q,r) = quotRem n 2
                x2 = sq x
 
mulMod :: Integral a => a -> a -> a -> a
mulMod a b c = (b * c) `mod` a
squareMod :: Integral a => a -> a -> a
squareMod a b = (b * b) `rem` a

-- (eq. to) powMod m n k = n^k `mod` m
powMod :: Integral a => a -> a -> a -> a
powMod m = pow' (mulMod m) (squareMod m)

Example:

-- check if '1212121' is prime with several witnesses
> map (millerRabinPrimality 1212121) [5432,1265,87532,8765,26]
[True,True,True,True,True]