# map -bytestring -base -text

O(n*min(n,W)). map f s is the set obtained by applying f to each element of s. It's worth noting that the size of the result may be smaller if, for some (x,y), x /= y && f x == f y
O(n). Map a function over all values in the map. > map (++ "x") (fromList [(5,"a"), (3,"b")]) == fromList [(3, "bx"), (5, "ax")]
O(n). Map a function over all values in the map. > map (++ "x") (fromList [(5,"a"), (3,"b")]) == fromList [(3, "bx"), (5, "ax")]
O(n*log n). map f s is the set obtained by applying f to each element of s. It's worth noting that the size of the result may be smaller if, for some (x,y), x /= y && f x == f y
O(n). The function mapAccum threads an accumulating argument through the map in ascending order of keys. > let f a b = (a ++ b, b ++ "X") > mapAccum f "Everything: " (fromList [(5,"a"), (3,"b")]) == ("Everything: ba", fromList [(3, "bX"), (5, "aX")])
O(n). The function mapAccum threads an accumulating argument through the map in ascending order of keys. > let f a b = (a ++ b, b ++ "X") > mapAccum f "Everything: " (fromList [(5,"a"), (3,"b")]) == ("Everything: ba", fromList [(3, "bX"), (5, "aX")])
O(n). The function mapAccumR threads an accumulating argument through the map in descending order of keys.
O(n). The function mapAccumR threads an accumulating argument through the map in descending order of keys.
O(n). The function mapAccumWithKey threads an accumulating argument through the map in ascending order of keys. > let f a k b = (a ++ " " ++ (show k) ++ "-" ++ b, b ++ "X") > mapAccumWithKey f "Everything:" (fromList [(5,"a"), (3,"b")]) == ("Everything: 3-b 5-a", fromList [(3, "bX"), (5, "aX")])
O(n). The function mapAccumWithKey threads an accumulating argument through the map in ascending order of keys. > let f a k b = (a ++ " " ++ (show k) ++ "-" ++ b, b ++ "X") > mapAccumWithKey f "Everything:" (fromList [(5,"a"), (3,"b")]) == ("Everything: 3-b 5-a", fromList [(3, "bX"), (5, "aX")])
Constructs a new array derived from the original array by applying a function to each of the elements.
Apply a function to transform the result of a continuation-passing computation. *  (mapCont f m) = f . runCont
Apply a function to transform the result of a continuation-passing computation. *  (mapContT f m) = f . runContT
O(n). Map values and separate the Left and Right results. > let f a = if a < "c" then Left a else Right a > mapEither f (fromList [(5,"a"), (3,"b"), (1,"x"), (7,"z")]) > == (fromList [(3,"b"), (5,"a")], fromList [(1,"x"), (7,"z")]) > > mapEither (\ a -> Right a) (fromList [(5,"a"), (3,"b"), (1,"x"), (7,"z")]) > == (empty, fromList [(5,"a"), (3,"b"), (1,"x"), (7,"z")])
O(n). Map values and separate the Left and Right results. > let f a = if a < "c" then Left a else Right a > mapEither f (fromList [(5,"a"), (3,"b"), (1,"x"), (7,"z")]) > == (fromList [(3,"b"), (5,"a")], fromList [(1,"x"), (7,"z")]) > > mapEither (\ a -> Right a) (fromList [(5,"a"), (3,"b"), (1,"x"), (7,"z")]) > == (empty, fromList [(5,"a"), (3,"b"), (1,"x"), (7,"z")])