[Haskell-beginners] Type Operator
byorgey at seas.upenn.edu
Wed Jan 21 22:07:00 EST 2009
On Wed, Jan 21, 2009 at 11:51:26PM +0100, Daniel Fischer wrote:
> I think you can't.
> If it's possible, the best option would be to change the order of type
> parameters of Sample. If that's not possible, you can define
> newtype FSample b a = FS (Sample a b)
> and make that an instance of Monad.
Right, Haskell doesn't allow partially applied type synonyms, but
partially applied newtypes are fine. It will just be a bit annoying
having the FS constructor tags everywhere. Switching the order of the
parameters to Sample would be the best option.
> Somebody remind me, why does Haskell not have type-lambdas?
Because type-lambdas would require higher-order unification during
type checking, which is in general undecidable. Without type lambdas,
if you have to unify two type applications like
f a == m b
then you know that f == m and a == b. But with type lambdas this
might not be the case. For example, you could have f == \x -> [x], a
= Int, m = \x -> x, and b = [Int].
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