[Haskell-beginners] pattern x:xs

[Luca Ciciriello]

Is it possible to use the pattern (x:xs) using a parallel array [::]?

In other words, is there a way to parallelize the code:

myfunc :: [:String:] -> [String]
myfunc [::] = []
myfunc (x:xs) = …

if I try to compile this I get the error:

Couldn't match expected type `[:String:]'
                with actual type `[t0]'
                In the pattern: x : xs

Is there a syntax in order to use the (x:xs) pattern?

Thanks in advance

Luca.