[Haskell-beginners] Imperfect Graham Scan

Brent Yorgey byorgey at seas.upenn.edu
Sun Jan 8 16:21:21 CET 2012


Did you actually try running grahamScan on the counterexample to see
what happens?

*GrahamScan> quickCheck prop_scan_idempotent 
*** Failed! Falsifiable (after 10 tests and 5 shrinks):    
[Point {x = -24.059102740955122, y = -21.293809017449384},Point {x =
-15.007588300013, y = -10.510812985305158},Point {x =
4.1243142492942395, y = -6.124011867063609},Point {x =
-14.22151555204262, y = -15.374749757396115}]

*GrahamScan> let ps = [Point {x = -24.059102740955122,
y = -21.293809017449384},Point {x = -15.007588300013, y =
-10.510812985305158},Point {x = 4.1243142492942395, y =
-6.124011867063609},Point {x = -14.22151555204262, y =
-15.374749757396115}]

*GrahamScan> grahamScan ps
[Point {x = -24.059102740955122, y = -21.293809017449384},Point {x =
-14.22151555204262, y = -15.374749757396115},Point {x =
4.1243142492942395, y = -6.124011867063609}]

*GrahamScan> (grahamScan . grahamScan) ps
[Point {x = -24.059102740955122, y = -21.293809017449384},Point {x =
4.1243142492942395, y = -6.124011867063609}]

It seems like each time 'grahamScan' is run on this list of points,
one point disappears from the end of the list.  I think the problem is
your 'scan' function, which can delete one of the points even when
there are only three points left.

-Brent

On Sun, Jan 08, 2012 at 03:31:44PM +0800, Zhi-Qiang Lei wrote:
> Hi,
> 
> The Graham Scan function I wrote, looks like running well. But when I put it in QuickCheck, it just failed in some case. Anyone can show me some clues about the problem? Thanks.
> 
> When I test it in ghci with some example, it returns the right result.
> *Main> let xs = [Point {x = 1.0, y = 1.0},Point {x = 0.0, y = 4.0},Point {x = 0.0, y = 6.0},Point {x = 3.0, y = 5.0},Point {x = 4.0, y = 4.0},Point {x = 4.0, y = 1.0},Point {x = 3.0, y = 3.0},Point {x = 2.0, y = 2.0},Point {x = 5.0, y = 5.0}]
> *Main> grahamScan xs
> [Point {x = 1.0, y = 1.0},Point {x = 4.0, y = 1.0},Point {x = 5.0, y = 5.0},Point {x = 0.0, y = 6.0},Point {x = 0.0, y = 4.0}]
> *Main> grahamScan it
> [Point {x = 1.0, y = 1.0},Point {x = 4.0, y = 1.0},Point {x = 5.0, y = 5.0},Point {x = 0.0, y = 6.0},Point {x = 0.0, y = 4.0}]
> 
> However, QuickCheck find some points which can fail it. Could it be a data type overflow problem?
> 
> prop_scan_idempotent xs = not (null xs) ==> (grahamScan . grahamScan) xs == grahamScan xs
> 
> *Main> quickCheck prop_scan_idempotent 
> *** Failed! Falsifiable (after 13 tests and 4 shrinks):    
> [Point {x = -6.29996952110807, y = -91.37172300100718},Point {x = 9.353314917365527, y = 64.35532141764591},Point {x = -23.826685687218355, y = 60.32049750442556},Point {x = -1.4281411275074123, y = 31.54197550020998},Point {x = -2.911218918860731, y = 15.564623822256719}]
> 
> === code ===
> module GrahamScan (grahamScan, Point(..))
> where
> 
> import Data.List
> import Data.Ratio
> 
> data Point = Point {
>     x :: Double,
>     y :: Double
> } deriving (Eq, Show)
> 
> instance Ord Point where
>     compare (Point x1 y1) (Point x2 y2) = compare (y1, x1) (y2, x2)
> 
> data Vector = Vector {
>     start   :: Point,
>     end     :: Point
> } deriving (Eq)
> 
> cosine :: Vector -> Double
> cosine (Vector (Point x1 y1) (Point x2 y2)) = (x2 - x1) / ((x2 - x1) ^ 2 + (y2 - y1) ^ 2)
> 
> instance Ord Vector where
>     compare a b = compare (f a) (f b) where
>         f = negate . cosine
> 
> sort' :: [Point] -> [Point]
> sort' xs = pivot : fmap end sortedVectors where
>     sortedVectors   = sort . fmap (Vector pivot) . delete pivot $ xs
>     pivot           = minimum xs
> 
> counterClockwise :: Point -> Point -> Point -> Bool
> counterClockwise (Point x1 y1) (Point x2 y2) (Point x3 y3) = (x2 - x1) * (y3 - y1) > (y2 - y1) * (x3 - x1)
> 
> scan :: [Point] -> [Point]
> scan (p1 : p2 : p3 : xs)
>     | counterClockwise p1 p2 p3 = p1 : scan (p2 : p3 : xs)
>     | otherwise                 = scan (p1 : p3 : xs)
> scan xs = xs
> 
> grahamScan :: [Point] -> [Point]
> grahamScan = scan . sort' . nub
> === code ===
> 
> 
> Best regards,
> Zhi-Qiang Lei
> zhiqiang.lei at gmail.com
> 
> 
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