[Haskell-beginners] Still confused

[Michael Peternell]

(/ 8)
is the same as
(\x -> x / 8)

you can think of it as
(HERE_IS_SOMETHING_MISSING / 8)

whereas
(/) 8
is normal function currying, i.e. it is the same as
(\x -> (/) 8 x)
or
(\x -> 8 / x)

just like
foo y
is the same as
(\x -> foo y x)
if foo is a function that takes 2 parameters.

on the other hand
(8 /)
is like
(8 / HERE_IS_SOMETHING_MISSING)
which translates to
(\x -> 8 / x)

Am 01.07.2013 um 20:03 schrieb Marc Gorenstein <marc.gorenstein at gmail.com>:

> Hi Brandon, Darren, and Michael,
> 
> Thanks for you responses, but I'm still confused. 
> 
> Here are two examples of operator sections. The first takes the infix operator 
> / and turns it into a prefix operator. 
> 
> Prelude> let eight_div_by = ((/) 8 )
> Prelude> eight_div_by 4
> 2.0
> 
> I get that. But look at the following:  We now have a prefix operator with 
> the input on the "wrong" side. 
> 
> Prelude> let div_by_eight = ( / 8 )
> Prelude> div_by_eight 4
> 0.5
> 
> Why should ( / 8) 4 = 0.5?
> 
> 
> Thanks again,
> 
> Marc
> 
> 
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