[Haskell-beginners] Question about Regular expression pattern consuming.

[S. H. Aegis]

Hi.
I'm newbie to Haskell.
I want to get date, it's type is [[String]].
The problem is that "the string that is used in regular expression pattern"
is consumed. ie, disappear.
Here is my code.

------------------------------------------------------------
import Text.Regex
import Control.Applicative

main :: IO()
main = do
    myIn <- readFile "Data.dat"
    print $ lines <$> intoEachPt myIn

intoEachPt :: String -> [String]
intoEachPt = splitRegex (mkRegex "20[0-9]{13}AH021")
-----------------------------------------------------------

How can I fix this?


Data:
....there is many DIGIT.....201306000300001AH02112361640
9.......

Output:
[[....there is many DIGIT..."],["12361640             9......]....]

I hope:
[[....there is many DIGIT..."],["201306000300001AH02112361640
9......]....]
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