[GHC] #1094: loop optimization by removing constants
GHC
trac at galois.com
Fri Jan 12 06:39:33 EST 2007
#1094: loop optimization by removing constants
--------------------------------+-------------------------------------------
Reporter: Azmo | Owner:
Type: feature request | Status: new
Priority: normal | Milestone: 6.8
Component: Compiler | Version: 6.6
Severity: normal | Keywords: loop constants optimization
Difficulty: Unknown | Testcase:
Architecture: Multiple | Os: Multiple
--------------------------------+-------------------------------------------
the current version of Data.List.foldl' is:
{{{
foldl' :: (a -> b -> a) -> a -> [b] -> a
foldl' f a [] = a
foldl' f a (x:xs) = let a' = f a x in a' `seq` foldl' f a' xs
}}}
which for some reason is faster if removing the first parameter, e.g:
{{{
foldl2' :: (a -> b -> a) -> a -> [b] -> a
foldl2' f = loop
where loop a [] = a
loop a (x:xs) = let a' = f a x in a' `seq` loop a' xs
}}}
----
Testing speed difference:
{{{
module Main (main) where
import System (getArgs)
sumFoldl' :: Int -> Int
sumFoldl' n = foldl' (+) 0 [1..n]
sumFoldl2' :: Int -> Int
sumFoldl2' n = foldl2' (+) 0 [1..n]
-- copy of Data.List.foldl'
foldl' :: (a -> b -> a) -> a -> [b] -> a
foldl' f a [] = a
foldl' f a (x:xs) = let a' = f a x in a' `seq` foldl' f a' xs
-- altered version of foldl'
foldl2' :: (a -> b -> a) -> a -> [b] -> a
foldl2' f = loop
where loop a [] = a
loop a (x:xs) = let a' = f a x in a' `seq` loop a' xs
main = do
[v,n] <- getArgs
case v of
"1" -> print (sumFoldl' (read n))
"2" -> print (sumFoldl2' (read n))
}}}
----
I have no idea how the optimization of loops is done, but the request is
that this kind of loop rewriting should be done by the compiler, not by
the user (to get a faster loop).
It seems to just be a matter of finding and removing constants
(identifiers just passed along).
--
Ticket URL: <http://hackage.haskell.org/trac/ghc/ticket/1094>
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