runghc -fglasgow-exts issues

[J. Garrett Morris]

This is not the exact answer to your question, but if the first line
of your .hs file is

{-# OPTIONS_GHC -fglasgow-exts #-}

then GHC extensions will be enabled within the file, whether compiled,
loaded in GHCi, or run with runghc.  Other compilers should ignore the
pragma (unlike the older {# OPTIONS #-})

 /g

On 12/1/06, Vyacheslav Akhmechet <coffeemug at gmail.com> wrote:
> I need to pass -fglasgow-exts to runghc. It appears that if the first
> flag to runghc is -f, it treats it as a path to GHC itself. So, I
> cannot do the following:
>
> > runghc -fglasgow-exts Test.hs
>
> because runghc failes (it says it can't find glasgow-exts). However if
> I do this:
>
> > runghc -fc:/ghc/bin/ghc.exe -fglasgow-exts Test.hs
>
> it works. Is this the expected behavior? I really don't want to pass
> full path to GHC in order to simply specify -fglasgow-exts.  I could
> fool runghc by doing this:
>
> > runghc -v -fc:/ghc/bin/ghc.exe -fglasgow-exts Test.hs
>
> and it'll work since the first argument isn't -f, but I really don't
> want to do this (if I have to, what's a good argument that does
> nothing?).
>
> Thanks,
>  - Slava.
> _______________________________________________
> Glasgow-haskell-users mailing list
> Glasgow-haskell-users at haskell.org
> http://www.haskell.org/mailman/listinfo/glasgow-haskell-users
>


-- 
It is myself I have never met, whose face is pasted on the underside of my mind.