[Haskell-cafe] Cannot understand liftM2
durden at gmail.com
Mon Dec 11 14:57:07 EST 2006
Hi All, Hi Cale,
Can you tell me if I understood things right ? Please see below ...
On 12/11/06, Cale Gibbard <cgibbard at gmail.com> wrote:
> The monad instance which is being used here is the instance for ((->)
> e) -- that is, functions from a fixed type e form a monad.
> So in this case:
> liftM2 :: (a1 -> a2 -> r) -> (e -> a1) -> (e -> a2) -> (e -> r)
> I bet you can guess what this does just by contemplating the type. (If
> it's not automatic, then it's good exercise) Now, why does it do that?
So the way I have to reason on the output I get from ghci is:
Prelude> :t liftM2
liftM2 :: (Monad m) => (a1 -> a2 -> r) -> m a1 -> m a2 -> m r
The m stands for ((->) e), that is like writing (e -> a1): a function
which will take an argument of type e and will return an argument of
And so the above line has a signature that reads something like:
liftM2 will takes 3 arguments:
- a function (-) that takes two arguments and returns one result of type r.
- a function (fst) that takes one argument and returns one result.
- a function (snd) that takes one argument and returns one result.
- the result will be a certain function that will return the same type
r of the (-) function.
- Overall to this liftM2 I will actually pass two values of type a1
and a2 and will get a result of type r.
>From the type signature - correct me if I am wrong - I cannot actually
tell that liftM2 will apply (-) to the rest of the expression, I can
only make a guess. I mean I know it now that you showed me:
> liftM2 f x y = do
> u <- x
> v <- y
> return (f u v)
If this is correct and it all makes sense, my next question is:
- How do I know - or how does the interpreter know - that the "m" of
this example is an instance of type ((->) e) ?
- Is it always like that for liftM2 ? Or is it like that only because
I used the function (-) ?
I am trying to understand this bit by bit I am sorry if this is either
very basic and easy stuff, or if all I wrote is completely wrong and I
did not understand anything. :D Feedback welcome.
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