[Haskell-cafe] why are implicit types different?
S. Alexander Jacobson
alex at alexjacobson.com
Tue Nov 21 14:18:50 EST 2006
Why do g and g' have different types?
g x y = let ?f = \x-> x in ?f x ++ (show (?f y))
g' x y = let f = \x-> x in f x ++ (show (f y))
Is there a way I can use implicit types and let g be as general as g'?
S. Alexander Jacobson tel:917-770-6565 http://alexjacobson.com
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