Re: [Haskell-cafe] Questions about the Functor class and it's use in "Data types à la carte"
jules at jellybean.co.uk
Sun Dec 16 08:49:55 EST 2007
jerzy.karczmarczuk at info.unicaen.fr wrote:
> Roberto Zunino writes:
>> without seq, there is no way to distinguish between undefined and (const
> "no way to distinguish" is perhaps too strong. They have slightly
> different types.
At a particular type which they both inhabit, such as (a->b) or, to be
concrete, (Int -> Int), there is no way to distinguish without seq.
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