[Haskell-cafe] Application of iterate
bjpop at csse.unimelb.edu.au
Fri Mar 23 07:41:55 EDT 2007
> It is :-
> my_sqrt t = last (take 20 (iterate (\n -> n/2 + t/(2 * n)) t))
> It is a bit crude though. 20 iterations is a bit arbitrary. I don't
> there is a easy way to iterate until the results stop changing.
Here's something for you to play with:
my_sqrt t = fix (\n -> n/2 + t/(2 * n)) t
fix :: (Double -> Double) -> Double -> Double
fix f x
| x == fx = x
| otherwise = f (fix f fx)
fx = f x
My numerical analysis is a bit on the dodgy side, but you probably don't
want to use == to test for convergence.
Maybe you can find a nice way to write fix using some prelude functions?
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