[Haskell-cafe] Dual Parser Failure???
byorgey at gmail.com
Sat Oct 13 10:02:47 EDT 2007
On 10/12/07, PR Stanley <prstanley at ntlworld.com> wrote:
> failure :: (Parser a) failure = \inp -> 
> The code might contain some syntax errors and I'd be grateful for any
> What is a "dual parser failure"?
You should probably put the definition on a separate line, thus:
failure :: (Parser a)
failure = \inp -> 
If that doesn't work, you could send along the definition of the Parser
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