[Haskell-cafe] Closures and pointfree functions

[Derek Elkins]

On Mon, 2007-09-03 at 19:47 +0200, Lars Oppermann wrote:
> Dear all,
> 
> In the Haskell Wiki at http://www.haskell.org/haskellwiki/Closure
> there is an example for a function returning a closure given as
>   f x = (\y -> x + y)
> 
> Another way to achieve the same effect would be to write
>   f' x = (+) x
> 
> which to me as a beginner looks somewhat like pointfree style.
> 
> Would f' be considered to return a closure

Going backwards:

Yes.

The pointfree "solution" in this case would simply be f' = (+)

Note that f x = \y -> x + y is written that way for emphasis and is
identical to f x y = x + y