[Haskell-cafe] reverse with foldl

[Rodrigo Queiro]

Prelude> :t foldl (\x -> \xs -> xs:x) []
foldl (\x -> \xs -> xs:x) [] :: [b] -> [b]

Strange choice of names, though, since x is a list, and xs is an
element. I would have gone for:
foldl (\xs x -> x:xs) []
although the library opts for:
foldl (flip (:)) []

On 21/09/2007, Miguel Mitrofanov <miguelimo38 at yandex.ru> wrote:
> > reverse = foldl (\x -> \xs -> xs:x) []
>
> Doesn't typecheck.
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