[Haskell-cafe] The range operator

[PR Stanley]

At 12:28 07/04/2008, you wrote:
>On Fri, Apr 4, 2008 at 10:49 PM, Andrew Coppin
><andrewcoppin at btinternet.com> wrote:
> >  More to the point, the range y..z goes in steps of y-z. ;-)
>[x,y..z] goes in steps of y-x ;-), [y..z] goes in steps of 1
>(depending on the type).


         Could you elaborate please?


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