[Haskell-cafe] Moving "forall" over type constructors
Klaus Ostermann
ko at daimi.au.dk
Mon Jun 9 09:55:20 EDT 2008
> But here we have an argument that can return a Wrapper (t a) for any
> 'a'; that does *not* mean it can return a wrapper of a polymorphic type.
> If you think about 'a' as an actual argument, then you could pass 'Int'
> to get a Wrapper (t Int), Bool to get a wrapper (t Bool), or even
> (forall a. a -> a) to get a Wrapper (t (forall a. a -> a)), but no
> argument at all could make a Wrapper (forall a. t a).
I just found out that it *is* possible to implement the inside function,
namely as follows:
> inside :: forall t. ((forall a. Wrapper (t a))-> Wrapper (forall a. (t
> a)))
> inside x = Wrapper f
> where f :: forall a. (t a)
> f = unwrap x
> unwrap (Wrapper z) = z
I guess this solves my problem. Sorry for bothering you with this question.
I still find it a bit weird to write all these obfuscated identity functions
to make the type checker happy, though.
Klaus
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