[Haskell-cafe] How does one delare a 2D STUArray in Haskell?
noteed at gmail.com
Fri Sep 25 03:51:08 EDT 2009
2009/9/25 minh thu <noteed at gmail.com>:
> 2009/9/25 Casey Hawthorne <caseyh at istar.ca>:
>> Well that makes sense, but for a learner, how is he/she supposed to
>> know that 'i' could be '(i,i)' or for that matter a tuple of n of
>> those i's?
>> "STUArray s i e"
>> Could you also have a tuple of states?
>> Obviosly, 'e' could be a tuple, for instance (Int,Char)
> Well, 'i' is just a type variable, just like 'a' and 'b' are type
> variables in the function type
> map :: (a -> b) -> [a] -> [b]
> I guess you know that you can "map" a suitable function on a list of
> pairs, right ?
> Type variable mean you can use whatever type you want, including
> pairs, lists, or whatever.
> So you can have list of whaterver you want, and use whatever you want
> as indices in arrays.... BUT!
> But the whatever you want can be constrained a bit: here, the
> constraint is that the type of the indices must be in Ix, this is what
> the "Ix i =>" means.
> For instance, we said we can put whatever you want in a list. But ask
> GHCi what is the type of
> inc = map (+1) :
> Prelude> :t map (+1)
> map (+1) :: (Num a) => [a] -> [a]
> You see that you can use "inc" on list of whatever you want (the "a")
> *provided* the "a" is in Num, the "Num a =>" part of the type
> Now, you have to look if the type you want to use for your indices is in Ix.
> Look at  and you see that
> (Ix a, Ix b) => Ix ((,) a b)
> is an Instance of Ix.
> (The right part can be read as (a,b) instead of (,) a b).
> So a pair is in Ix provided its elements are in Ix too.
>  http://hackage.haskell.org/packages/archive/base/220.127.116.11/doc/html/GHC-Arr.html#t%3AIx
Forget to say this:
You don't have a pair of indices or a pair of states: you have an
index which is a pair, and you can have a state which is a pair.
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