[Haskell-cafe] Re: Implementing "unionAll"

[Ozgur Akgun]

> The easiest solution is simply to define
>
>    unionAll = nub . mergeAll
>        where
>        -- specialized definition of  nub
>        nub = map head . groupBy (==)
>
>

Talking about the easiest solution, I guess this is a quite easy way of
defining unionAll as well: http://gist.github.com/306782
I, of course, do not claim that it is more efficient or better. But I don't
think it'd be rubbish :)


-- 
Ozgur Akgun
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