[Haskell-cafe] Template Haskell - substitution in pattern in a lambda

[Antoine Latter]

On Sun, Jan 3, 2010 at 8:30 PM, Patrick Caldon <patc at pessce.net> wrote:
>
> I'm trying to write some template haskell which will transform:
>
> $(buildCP 0)  into \(SimpleM d1 d2 d3) (SimpleM _ _ _) -> (SimpleM d1 d2 d3)
> $(buildCP 1)  into \(SimpleM _ d2 d3) (SimpleM d1 _ _) -> (SimpleM d1 d2 d3)
> $(buildCP 1)  into \(SimpleM d1 _ d3) (SimpleM _ d2 _) -> (SimpleM d1 d2 d3)
> and so on.
>
> Ultimately I want to generalize this to more variables.
>
> I can't seem to get anything to substitute for the pattern variables in a
> lambda.  Is there a straightforward way of doing this?
>

Hello,

It looks like you want to construct expressions with the LamE
constructor, which is declared like so:

LamE [Pat] Exp

For the Pat, you would use eiter VarP or WildP for variable binding
patterns or wild-card patterns.

Or am I missing something?

Antoine