[Haskell-cafe] Re: Can we come out of a monad?

[Ivan Lazar Miljenovic]

Ertugrul Soeylemez <es at ertes.de> writes:

> Hello,
>
> it's a bit hidden in Haskell, but a monad instance consists of three
> functions:
>
>   fmap   :: (a -> b) -> (m a -> m b)

You don't even need fmap defined for it to be a monad, since fmap f m =
liftM f m = m >>= (return . f)

-- 
Ivan Lazar Miljenovic
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IvanMiljenovic.wordpress.com