[Haskell-cafe] Please help : Data.Time.Format parseTime

[Vincent Gerard]

Hello Dmitri,

It seems that your format pattern does not match exactly the format of
the input, thus the parser returns Nothing.

Try the following format string which seems to work with your date:

parseTime defaultTimeLocale "%m/%d/%Y %l:%M:%S %p" ds :: Maybe
UTCTime returns : Just 2009-10-11 19:04:28 UTC

The parsings errors in your format could come from 
 .  %D expects a 2 char year
 .  %H expects a 0 padded hour (like 07, not 7)

Regards,

Vincent Gerard

On Wed, 15 Jun 2011 00:33:56 +0400
"Dmitri O.Kondratiev" <dokondr at gmail.com> wrote:

> I am trying to convert data string to time:
> 
> import Data.Time
> import Data.Time.Format
> import Locale
> 
> ds = "10/11/2009 7:04:28 PM"
> t = parseTime defaultTimeLocale "%D %H:%M:%S  %p" ds :: Maybe UTCTime
> 
> and get "Nothing".
> What is wrong?
> 
> Thanks !
> Dmitri.